The factor that CITES fail to consider when determining which species to cover is the Ecosystem sustainability.
A sustainable ecosystem is a biological environment with a series of habitats that is able to thrive and also support itself without outside influence. it is the capacity of the biosphere to meet the needs of the present generation, without hindering future generations from being able to meet their needs.
The correct answer is C. Here's why:
Choice A is illogical. A single experiment does not confirm a theory as true. Multiple successful trials are needed for one to even consider a hypothesis to be accepted as a theory.
Choice B is wrong. If a scientist finds a new way to test a hypothesis, experimental methods do change. Note that when there are additional ways to test a hypothesis, a scientist should test it with additional methods.
Choice D is incorrect. If someone finds a way to test a new hypothesis, it would not be made into law since there is more information regarding the theory. This means that it would remain a theory until one can prove that it can't be tested using different methods.
The order from what I remember is
Interphase
Prophase
Metaphase
Anaphase
Telophase
Cytokinesis- also known as daughter cells
Nitrogen Fixation: Root and Bacteria Interactions. Nitrogen is an important macronutrient because it is part of nucleic acids and proteins. ... The most important source of BNF is the symbiotic interaction between soil bacteria and legume plants, including many crops important to humans.
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
