i belive 60% becuse it lands on heads 60 time out of a hudred
Since only the principal value, interest rate and interest period are given, we can deduce that "finance charge" only includes the interest to be paid at the end of the term. This can be obtained by subtracting the principal value from the future value which we will solve for.
The future value can be solved by using the following compound interest formula:
Let:
F = Future value
P = Principal value
r<span> = annual interest rate </span>
n<span> = number of times that interest is compounded per year</span>
t<span> = number of years</span>
F = P(1 + r/n)^nt
Substituting the given values:
F = 4250(1 + 0.1325/12)^(12*2)
F = 5531.54
Subtracting P from F:
Finance charge = 5531.54 - 4250 = 1281.54
Therefore the finance charge is $1,281.54
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
Top left and bottom right yes the rest no
100+x (s)+68.25(t)=a
S=shirts
T=trophies
A=amount paid
