There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
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The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following
perimeter and area of the trapezium.
<h3>How can the area and perimeter of the trapezium be found?</h3>
The perimeter of a trapezoid is given as follows;
Perimeter = The sum of the lengths of the sides
Which gives;
Perimeter = 6 + 7 + 6.5 + 9.5 = 29
The perimeter of the trapezoid =<u> 29 cm</u>
The area of the trapezoid is given as follows;

Which gives;

The area of the trapezoid = 49.5 cm²
Learn more about the area and perimeter of geometric shapes here:
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brainly.com/question/11461461
Answer is B, because 8*8=64 and 9*9=81. 76 lies between 64 and 81.