A ratio of 3:2.
The easiest way to go about this is to divide the actual number of wins (18) by its corresponding element in the ratio.
So:
This means every element on the ratio has a value of 6.
The amount of element in the ratio that correspond to losses is 2.
Multiply the actual amount of matches per element in the ratio by the number of elements that represents the losses in the ratio.
Your answer:
<em>"The team lost 12 games."</em>
Answer:
Step-by-step explanation:
in tri ADC and tri BDC
∠ADC =∠BDC = 90
DC is common
AD = BD (given)
triangle ADC ≅ tri BDC by SAS congruency
hence AC = BC by CPCT ( congruent parts of congruent triangles)
hence, BC = 13
The answer is 573
S is the three digit number.
h - a number of hundreds
t - a number of tens
o - a number of ones
S = 100h + 10t + o
<span>The last two digits add to make ten: t + o = 10
</span><span>The first and last digits add to make eight: h + o = 8
</span><span>The first two digits add to make twelve: h + t = 12
</span>t + o = 10 ⇒ o = 10 - t
h + o = 8 ⇒ o = 8 - h
_______
10 - t = 8 - h
h + t = 12 ⇒ h = 12 - t
_______
10 - t = 8 - (12 - t)
10 - t = 8 - 12 + t
10 - t = -4 + t
10 + 4 = t + t
2t = 14
t = 14/2 = 7
______
h = 12 - t = 12 - 7 = 5
______
o = 8 - h = 8 - 5 = 3
S = 100h + 10t + o
h = 5
t = 7
o = 3
S = 100*5 + 10*7 + 3
= 500 + 70 + 3
= 573
6.66, with a bar on top of the last two sixes
