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3 years ago

Which of the following could be the numbers of left-handed and right-handed students at West Junior

Mathematics

1 answer:

nordsb [41]3 years ago

3 0

Answer:

The anwers Is C and E.

Step-by-step explanation:

A relationship between two quantities is proportional if the ratio between those quantities is always equivalent.

Hint #22 / 4

Let's look at the ratio between right- and left-handed students at East Middle School.

right

left

right per left

58left

609right

=10.5 right per left

At East Middle School, there are

10.5 right-handed students for every left-handed student.

Hint #33 / 4

Now we can compare the other combinations of values for left-handed and right-handed students. Which ratios are equivalent to the ratio at East Middle School?

So the anwers is C AND E

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3 years ago

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beks73 [17]

Answer:

The answer is the first R

Step-by-step explanation:

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3 years ago

Write the equation of a line that includes the point (22, 12) and

STatiana [176]

Let's start with y = 4x + b (since 4 is the slope);

We need to find what number should be put instead of b;

Then, let's see what needs to be done;

Plug in the y and x values from the coordinate (22,12) into y=4x+b;

12 = 4(22) + b

Solve;

12 = 88 + b

12 - 88 = b

b = -76

Remember the equation y = 4x + b? Put the -76 instead of b:

y = 4x + -76

or: y = 4x - 76

That is the equation.

To make it standard form, put x and y both in the left side, with x first then y:

-4x + y = -76

^^Answer!

7 0

3 years ago

Question 1(Multiple Choice Worth 3 points) (02.06)The table below shows that 1 day equals 24 hours. Notice that 12 hours is one-

g100num [7]

9514 1404 393

Answer:

2 1/4 days

Step-by-step explanation:

You could extend your table a bit to help answer this.

(days, hours)

(1, 24)

(1/2, 12)

(1/4, 6)

(2, 48)

Now, we observe that 54 hours is 6 more hours than 48 hours, so will be 1/4 day more than 2 days.

54 hours is 2 1/4 days

4 0

4 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

$x^3y'' + 2x^2y' + 4y$

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ; $x=x_o$ is located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

$y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0$

$y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0$

The standard form of the differential equation is :

$\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0$

Thus;

$P(x) = \dfrac{2}{x}$

$Q(x) = \dfrac{4}{x^3}$

The zeros of $x,x^3$ is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x) and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = $x*\dfrac{2}{x}$

p(x) = 2

q(x) = x²Q(x)

q(x) = $x^2 * \dfrac{4}{x^3}$

q(x) = $\dfrac{4}{x}$

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic at x = 0

$Q(x) = \dfrac{4}{x^3}$ do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0

3 years ago