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3 years ago

NEVERMIND I GOT THE ANSWERquestion in photo, i cant do math help :(

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

5 0

|EG| / |FH| = |GD| /|HD|

6/8 = |GD|/14

|GD| =6*14/8 = 10.5

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Need help with this question, please help!

lubasha [3.4K]

Answer:

x = 1 in

Step-by-step explanation:

We can use ratios to solve since they are similar triangles

6 6+x

----- = ---------

5 6

Using cross products

6*6 = 5*(6+x)

36 = 30+6x

Subtract 30 from each side

36-30 = 30-30+6x

6 = 6x

Divide each side by 6

6/6 = 6x/6

1 =x

6 0

3 years ago

What are all the fractions are equivalent to 4/12

GarryVolchara [31]

The answers are 1/3, 2/6, 3/9, 4/12

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3 years ago

The probability of a detasseler making less than $17/hr is ≈ %.

ELEN [110]

Answer:

99%

Step-by-step explanation:

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4 years ago

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$

Multiply both sides by 16:

$(16x^2+32x+16)+(9x^2-54x+81) = 256$

Combine like terms:

$25x^2+-22x+97=256$

Isolate the equation:

$\displaystyle 25x^2 - 22x -159=0$

We can use the quadratic formula:

$\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 25, b = -22, and c = -159. Substitute:

$\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}$

Evaluate:

$\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}$

Hence, our two solutions are:

$\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}$

We have our two x-coordinates.

To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

$\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2$

And:

$\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}$

Thus, our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

6 0

3 years ago

A scale has a percent error of 7%. The scale reads the mass of a book as 450 g.

melisa1 [442]

Answer:

The actual mass is either 453 or 447

Step-by-step explanation:

7 percent of 450

= (7/100) * 45

= 3.15

error = 3.15 g

hence actual mass

= 450 + 3.15

= 453.15

= 450 - 3.15

= 446.85

5 0

3 years ago