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grandymaker [24]
3 years ago
12

A baby whale gains about 250 pounds a day. It was 250 pounds at birth. Find an equation to find the number of days it will take

for a baby to weigh its first ton.
Mathematics
2 answers:
Masteriza [31]3 years ago
5 0

Answer:

250*x+250

Step-by-step explanation:

x is the number of days the baby gains pounds.

meriva3 years ago
4 0

Answer:

8 days

Step-by-step explanation:

1 ton=2,000 pounds and If you divide 2,000÷250=8 days. It will talk 8 days for the baby whale to weigh his first ton.

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3 0
4 years ago
Determine the rate of change of the following linear equation as it translates from (-5, -1) to any other point on the line.
anzhelika [568]

The rate of change of the linear equation is -\frac{2}{3}

Explanation:

The given two coordinates are (-5,-1) and (1,-5)

To determine the rate of change, let us use the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the coordinates in the equation, we get,

m=\frac{-5+1}{1+5}

Simplifying, we have,

m=\frac{-4}{6}

Dividing, we get,

m=-\frac{2}{3}

Thus, the rate of change of the linear equation is -\frac{2}{3}

7 0
3 years ago
Two boats on opposite banks of a river start moving towards each other. They first pass each other 1400 meters from one bank. Th
Nesterboy [21]

S1 = speed of boat 1

<span> t1 =  time to do 1400 meters (boat 1) </span>

S1*t1 = 1400

<span><span>S2  </span>= speed of boat 2 </span>

1400 + S2*t1 = X

t2 = time to do X + 600 (boat 2)

S1*t2 = X + 600

S2*t2 = 2X - 600

S1 = 1400/t1

S2 = (X-1400)/t1

<span>T = t2/t1  </span>

1400*T = X + 600

X*T - 1400*T = 2X - 600

X = 3600 meters

<span> River is 3600 meters wide</span>


8 0
3 years ago
What are the zeros of the polynomial function f(x)=x^3-5x^2-6x ?
iren2701 [21]

Option C

The zeros of the polynomial function f(x) = x^3 - 5x^2 - 6x is x = 0 and x = -1 and x = 6

<h3><u>Solution:</u></h3>

Given that polynomial function is f(x) = x^3 - 5x^2 - 6x

We have to find the zeros of polynomial

To find zeros, equate the given polynomial function to 0. i.e f(x) = 0

x^3 - 5x^2 - 6x = 0

Taking "x" as common term,

x(x^2 - 5x - 6) = 0

Equating each term to zero, we get

x=0 \text { and } x^{2}-5 x-6=0

Thus one of the zeros of function is x = 0

Now let us solve x^{2}-5 x-6=0

We can rewrite -5x as -6x + x

x^2 + x - 6x - 6 = 0

Taking "x" as common from first two terms and -6 as common from next two terms

x(x + 1) -6(x + 1) = 0

Taking (x + 1) as common term,

(x + 1)(x - 6) = 0

x + 1 = 0 and x - 6 = 0

x = -1 and x = 6

Thus the zeros of given function is x = 0 and x = -1 and x = 6

3 0
3 years ago
Read 2 more answers
6000 as a whole number multiplied by a power of 10
il63 [147K]
The answer is 60,000
8 0
3 years ago
Read 2 more answers
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