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2 years ago

Ustrating the fine basic

Mathematics

1 answer:

alukav5142 [94]2 years ago

8 0

Answer:$249895.46

Step-by-step explanation:

Well, if 2250 dollars increase by 17% every year for 30 years, then it will be 2250*(1.17)^30

which would be $249895.46

so if you could increase money by 17% every year, 2250 dollars now will be worth a lot in 30 years!

You might be interested in

Use the slope of the given line to construct a parallel line

Troyanec [42]

Answer:

y = - $\frac{4}{3}$ x - 7

Step-by-step explanation:

Parallel lines have equal slopes.

Calculate the slope m of the given line using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (3, - 2) ← 2 points on the line

m = $\frac{-2-2}{3-0}$ = - $\frac{4}{3}$ , thus

y = - $\frac{4}{3}$ x + c ← is the partial equation

To find c substitute P(- 3, - 3) into the partial equation

- 3 = 4 + c ⇒ c = - 3 - 4 = - 7

y = - $\frac{4}{3}$ x - 7 ← equation of parallel line

6 0

3 years ago

Read 2 more answers

Rectangle A is a scale drawing of Rectangle B and has 25% of its area. If rectangle A has side lengths of 4 cm and 5 cm , what a

SpyIntel [72]

Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

Rectangle A is a scale drawing of Rectangle B and has 25% of its area

in other words

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\$

Step 2

Let

Rectangle A

length (1)= 4 cm

length (2)= 5 cm

$Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}$

put this value into equation 1

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\ Area_{B}=80\ cm^{2}$

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

$Area_{B}=80\ cm^{2}\\length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\$

the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

$\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)} \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)$

Step three

using Eq 1 and Eq 2 find the lengths

put the value of length(1B) into equation (2)

$length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm$