Which list of numbers is in order from least to greatest?

Dwayne wrote a two-digit number. He multiplied it by 3, added 18, and divided by 8. His final answer was 9. What number did Duwa

Karolina [17]

Question 1:
(x*3)+18/8=9 is the equation
(x*3)+18=72 multiply by 8
(x*3)=54 Subtract 18
x=18 Divide by 3

The two digit number is 18

Question 2:
x*4=43 Divide by 4
x=10.75 10 3/4
10 3/4+3 3/4 Solve
14 1/2

Pablo is 14 1/2 years old

8 0

3 years ago

Write a polynomial equation in standard form with roots of -3 and 4

liubo4ka [24]

Answer:

I don't know the answer

Step-by-step explanation:

the most seats in guyan

6 0

2 years ago

GIVING BRANIEST FOR #5

Flura [38]

Answer:

we need to see the other page or we cant solve it

Step-by-step explanation:

6 0

2 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labelled 2, and six are labelled 3. Let the random v

Dima020 [189]

Answer: 2.36

Step-by-step explanation:

Using the μ=∑[x⋅P(X=x)

U will need to do

2/11 because you have 2 labeled 1

3/11 because you have 3 labeled 2

6/11 because you have 6 labeled 3

Then you will do:

1 x 2/11 = 0.18

2 x 3/11 = 0.5454 = 0.55

3 x 6/11 = 1.63

Then add them all together to find the μ

0.18 + 0.55 + 1.63 = 2.36

Hope that helps, plz put a good rating

4 0

2 years ago