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3 years ago

14

Which list of numbers is in order from least to greatest?

1 answer:

laiz [17]3 years ago

8 0

Answer:

its A 22%

Step-by-step explanation:

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Pls help I really need it

tangare [24]

Answer:

x = 20

p =54

y= 54

Step-by-step explanation:

2x-4 = 96-3x

5x = 100

x = 20

2x-4 = 40-4 = 36

(180 - (36 x 2))/2

(180-72)/2

108/2

p = y =54

5 0

2 years ago

A road sign has the shape of an equilateral triangle with a side length of 48 inches. What is the height of the sign? The road s

Ivenika [448]

The height of the equilateral triangle is 41. 6 inches. Option C

<h3>How to determine the height</h3>

The formula for finding the height of an equilateral triangle is given as;

h = (a√3)/2

we have a = 48 inches

Let's substitute the value

Height, h = $\frac{48\sqrt{3} }{2}$

Height = $\frac{48 * 1. 732}{2}$

Height = $\frac{83. 14}{2}$

Height = $41. 6$ Inches

Thus, the height of the equilateral triangle is 41. 6 inches. Option C

Learn more about equilateral triangles here:

brainly.com/question/1399707

#SPJ1

5 0

1 year ago

Y=4x+8 y=-x-7 solve by substitution

nikklg [1K]

Step-by-step explanation:

Alrighty! here you go image.

7 0

2 years ago

Read 2 more answers

Brandy is making a peach pie for her grandmother for christmas. the diameter of the pie is 12 in. if three-fourths of the area o

Mariulka [41]

Roughly 84 square in

4 0

2 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago