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Nataliya [291]
3 years ago
8

If f(n+1)=f(n)-8if f(1)=100what is f(6)

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0

The value of f(6) is f(6)=60

Explanation:

The equation is f(n+1)=f(n)-8

It is given that f(1)=100

Now, we shall determine the value of f(6)

Let us substitute n=1,2,3,4,5 in the equation f(n+1)=f(n)-8

For n=1,

\begin{aligned}f(1+1) &=f(1)-8 \\f(2) &=100-8 \\&=92\end{aligned}

Thus, when n=1 ⇒ f(2)=92

For n=2,

\begin{aligned}f(2+1) &=f(2)-8 \\f(3) &=92-8 \\&=84\end{aligned}

Thus, when n=2 ⇒ f(3)=84

For n=3 ,

\begin{aligned}f(3+1) &=f(3)-8 \\f(4) &=84-8 \\&=76\end{aligned}

Thus, when n=3 ⇒ f(4)=76

For n=4,

\begin{aligned}f(4+1) &=f(4)-8 \\f(5) &=76-8 \\&=68\end{aligned}

Thus, when n=4 ⇒ f(5)=68

For n=5,

\begin{aligned}f(5+1) &=f(5)-8 \\f(6) &=68-8 \\&=60\end{aligned}

Thus, when n=5 ⇒ f(6)=60

Hence, the value of f(6) is f(6)=60

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4 years ago
Each bottle of apple juice costs $2.40 and each bottle of orange juice costs $2.20. If James has $50.80 and wants to buy 10 bott
elena-14-01-66 [18.8K]

Answer:

12

Step-by-step explanation:

Orange juice: $2.20 per bottle.

10 bottles of orange juice cost 10 * $2.20 = $22.00.

We subtract the cost of the 10 bottles of orange juice from the amount of money he has to find out the amount he will have left for bottles of apple juice.

$50.80 - $22.00 = $28.80

After buying the 10 bottles of orange juice, he has $28.80 left.

We divide the money he has left for apple juice bottles by the price of one apple juice bottle to find out the number of apple juice bottles he can buy.

$28.80/$2.40 = 12

He can buy 12 bottles of apple juice.

6 0
4 years ago
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aivan3 [116]

Answer:

asdasd

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
23.
Crazy boy [7]

Answer:

The number that cannot be the largest possible 6-digit number is;

(D) AAABCB

Step-by-step explanation:

From the question, we have;

A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

When C > A > B

The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;

AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB

∴ AAABBC > AAABCB and <u>AAABCB</u>, cannot be the largest possible 6-digit number

3 0
3 years ago
Question 5 of 20
Dmitry_Shevchenko [17]
I’m going to say B I could be wrong
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3 years ago
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