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Mademuasel [1]
2 years ago
5

When two statements are connected with the word and , the new statement is called a

Mathematics
2 answers:
Nutka1998 [239]2 years ago
4 0

Answer:

disjunction

Step-by-step explanation:

SVETLANKA909090 [29]2 years ago
3 0
Disjunction!
explanation: correct on edge2021
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I need help please thanks.
padilas [110]

Answer:

w =20.3

Step-by-step explanation:

<em>i</em><em> </em><em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em>s</em><em> </em><em>y</em><em>o</em><em>u</em><em> </em><em>s</em><em>o</em><em>r</em><em>r</em><em>y</em><em> </em><em>i</em><em> </em><em>w</em><em>a</em><em>s</em><em> </em><em>l</em><em>a</em><em>t</em><em>e</em><em> </em><em>f</em><em>o</em><em>r</em><em> </em><em>y</em><em>o</em><em>u</em><em>r</em><em> </em><em>l</em><em>a</em><em>s</em><em>t</em><em> </em><em>q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em>.</em>

5 0
3 years ago
Read 2 more answers
Write the first five terms of the sequence defined by the recursive formula
Arada [10]

Answer:

The second option is the correct answer

The sequence is : 0, -1, -6, -31, -156

Step-by-step explanation:

It is given that,  

The recursive formula , an = 5a(n-1) - 1 and a1 = 0

<u>To find a2, a3, a4, a5 </u>

a2 = 5a1 -1 = 5x0 - 1 = -1

a3 = 5a2 - 1 = (5x -1 ) - 1 = - 5 - 1 = -6

a4 = 5a3 - 1 =(5x -6) - 1 = -30 - 1= -31

a5 = 5a4 - 1 = (5 x -31 ) - 1 = -155 -1 = -156

Therefore the resulting sequence is

0, -1, -6, -31 ,-156



6 0
3 years ago
Read 2 more answers
I don't get this. Please please please help!!!
shusha [124]
Don't get what................................................
8 0
2 years ago
I need help with this please
MA_775_DIABLO [31]

it is the last one im pretty sure

6 0
2 years ago
Find the value or measure. Assume all lines that appear to be tangent are tangent. X=
aev [14]

According to the secant-tangent theorem, we have the following expression:

(x+3)^2=10.8(19.2+10.8)

Now, we solve for <em>x</em>.

\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}

Then, we use the quadratic formula:

x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Where a = 1, b = 6, and c = -315.

\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}<h2>Hence, the answer is 15 because lengths can't be negative.</h2>
7 0
1 year ago
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