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3 years ago

PLEASE HELP I GIVE BRAINLIEST I NEED IT ASAP

Mathematics

2 answers:

tigry1 [53]3 years ago

7 0

Answer:

D 13

Step-by-step explanation: L+L+W+W=Perimeter

2(1/4x)+2(2x+1)=4.5x+2

4.5x+2=29 Subtract 2

4.5x=27 Divide by 4.5

x=6 1/4(6)= 1.5 W=1.5 1.5(2)=3

2(6)+1=13 13(2)=26

26+3=29inches perimeter

kompoz [17]3 years ago

6 0

Answer:

A: 12 4/9

Step-by-step explanation:

1/4x (2x + 1) = 29 (Combine like terms, NOT distributive property!!!)

2 1/4x + 1 = 29

- 1 - 1

2 1/4 / 2 1/4x = 28 / 2 1/4

x = 12 4/9

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Negative 22 minus 16

Maru [420]

The answer is -38.

$-22-16=-38$

4 0

3 years ago

Read 2 more answers

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

3 years ago

If p(x) = x + 3, then p(x) + p(–x) is equal to ??

lina2011 [118]

Answer:

The answer is 6

Step-by-step explanation:

p(x) = x + 3

p(-x) = -x + 3

=> p(x) + p(-x) = x + 3 + (-x) + 3 = 6

Hope this helps!

5 0

3 years ago

6 - 2x ≤ 12 or 7 + 2x < -11

Phoenix [80]

Answer: X< -9

Step-by-step explanation: 7+2x<-11 move the constant to the right and change its sign. 2x<-11-7. Now calculate the difference, which should get to... 2x<-18. Then you just divide both sides of the inequality by 2. Which should get your answer.... X< -9

4 0

3 years ago

Please help me with this question!!

tester [92]

Answer:

Step-by-step explanation:

Pythagorean Theorem is "a^2+b^2=c^2"

Step 1) 1^2+6^2=37

37=c^2

Step 2) The square root of 37 is 6.08

That's not 9

So they don't form a Pythagorean triple

5 0

3 years ago