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LenKa [72]
3 years ago
8

Can someone help me out please?? I would really appreciate it.

Mathematics
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

C: x = 5 and y = (5√3)/2

Step-by-step explanation:

Looking at the triangle, we can use trigonometric ratios to find x and y since it's a right angled triangle.

Thus;

(5/2)/x = sin 30

x = (5/2)/½

x = 5

Similarly, (5/2)/y = tan 30

tan 30 in surd form is 1/√3

Thus;

(5/2)/y = 1/√3

y = 5/2 × √3

y = (5√3)/2

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allsm [11]
50 becacause there is 27 and you need to add it all together
8 0
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Point p is the midpoint of DE. DP =3x + 2 and DE = 10x - 12. What is the length of DP
shepuryov [24]
If P <span>is the midpoint of DE then 
DE = 2(DP)
10x - 12 = 2(3x + 2)
10x - 12 = 6x + 4
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6 0
3 years ago
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Mark A machine has two parts labeled A and B. The probability that part A works for one year is 0.8 and the probability that par
Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that P(A) = 0.8, P(B) = 0.6

The probability that at least one part works for one year is 0.9.

This means that: P(A \cup B) = 0.9

We also have that:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

0.9 = 0.8+0.6 - P(A \cap B)

P(A \cap B) = 0.5

Calculate the probability that part B works for one year, given that part A works for one year.

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0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

3 0
2 years ago
Use long division to divide x^3+x^2-2x+14 by x+3
bekas [8.4K]

First, x^3=x^2\cdot x, and if we multiply x+3 by x^2 we get

x^3+3x^2

Subtracting this from the numerator gives a remainder of

-2x^2-2x+14

Next, -2x^2=-2x\cdot x, and if we multiply x+3 by -2x we have

-2x^2-6x

and subtracting this from the previous remainder, we end up with a new remainder of

4x+14

Next, 4x=4\cdot x, and if we multiply x+3 by 4 we get

4x+12

Subtracting from the previous remainder, we get a new remainder of

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which contains no more factors of x, so we're done.

So,

\dfrac{x^3+x^2-2x+14}{x+3}=x^2-2x+4+\dfrac2{x+3}

8 0
3 years ago
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Sindrei [870]

Answer:

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Step-by-step explanation:

connecting the dots would create the slope

7 0
3 years ago
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