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NemiM [27]
3 years ago
15

2

48-3 \sqrt{x} 12+3\\ 27" alt="\sqrt{x} 48-3 \sqrt{x} 12+3\\ 27" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer:

This problem is not possible.

Step-by-step explanation:

Only functions and variables can have subscripts, or the number below the first 2. If we were to take that out, then we would get a line that starts at y = 8 and goes up on the x axis.

Hope that this helps!

You might be interested in
.. an. v. . it V V is going on afield trip to Austin to of Texas History and lo see an I MAX Ruiz day given the number of hours
erastova [34]
This is one of those problems where you'll sink like a rock if
you allow yourself to be blinded by all the useless, unnecessary,
irrelevant information in the first paragraph.

The ONLY information you need is:

-- You're chartering a bus for 1 day.
-- It costs  $780 .

That's ALL .

(You don't even need to know that the bus has 55 seats.
You might need that for #8 - #12, but not for #6 or #7.)
_________________________

If the people on the trip are going to share the cost of the bus,
then the cost of each share depends on the number of people.

             Less people ==> each one pays more.
             More people ==> each one pays less.

Just like everybody in the office sharing the cost of
a birthday gift for the boss.

#6 and #7 should really be done in the reverse order ...
do #7 before you worry about #6.
Before you can fill in the table in #6, you absolutely need
to have the equation, whether or not you realize it.

The total cost is fixed . . . It's $780 .

If 2 people go on the trip, each one pays  780 / 2 .
If 3 people go on the trip, each one pays  780 / 3 .
If 4 people go on the trip, each one pays  780 / 4 .
If 5 people go on the trip, each one pays  780 / 5 .
.
.
If 10 people go on the trip, each one pays  780 / 10 .
.
.
If 20 people go on the trip, each one pays  780 / 20 .
.
.
If ' n ' people go on the trip, each one pays  780 / n .
.
.  until the bus is full ...
.
If 55 people go on the trip, each one pays  780 / 55 .
.
If 56 people go on the trip, then you need another bus,
and it gets more complicated.

But up to 55, the price per person is (780 / the number of people).

<span>  #7).             P  =  780 / n .

</span>Now, filling in the table in #6 is a piece 'o cake.<span>

</span>5 people. . . . . . . 780 / 5
10 people . . . . . 780 / 10
15 people . . . . . 780 / 15
20 people . . . . . 780 / 20
.
.
etc.

Just don't go past 55 people.  The equation changes after that.

For ANY number of people, even hundreds, and ANY number
of buses, I think the equation looks something like this:

                P  =  (785/n) · [ 1 + int(n/56) ]  .

' int ' means ' the greatest integer in ... ', that is,
                     ' throw away the fractional part of the quotient,
                       and use only the whole number '.


5 0
3 years ago
Answer the following questions.
schepotkina [342]
<h3><u>Answer the following questions :-</u></h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind  \: of\:junk} & \bf{Price  \: of \:  1  \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \:  Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: newspaper = Rs.5}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  20  \: kg  \: newspaper = Rs.20 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  20  \: kg  \: newspaper = Rs.100}}}

\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost  \: of \:  20  \: kg  \: newspaper = Rs.100}}}}}}

<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

\rule{200}{1.5}

2. What is the cost of 5 kg Iron?

\quad{\longrightarrow{\sf{Cost\: of \:  1  \: kg  \: iron = Rs.10}}}

\quad{\longrightarrow{\sf{Cost\: of \:  5  \: kg  \: iron = Rs.10 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  5  \: kg  \: iron = Rs.50}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: iron = Rs.50}}}}}

<u>∴ The cost of 5 kg iron is Rs.50.</u>

\rule{200}{1.5}

3. What is the cost of 9 kg Plastic?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: plastic = Rs.8}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.8 \times 9}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.72}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \:  9  \: kg  \: plastic = Rs.72}}}}}

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

\rule{200}{1.5}

4. What is the cost of 7 kg Brass?

\quad{\longrightarrow{\sf{Cost  \: of \:  1  \: kg  \: brass = Rs.50}}}

\quad{\longrightarrow{\sf{Cost\: of \:  7  \: kg  \: brass = Rs.50 \times 7}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  7  \: kg  \: brass = Rs.350}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: brass = Rs.350}}}}}

<u>∴ The cost of 7kg brass is Rs.350.</u>

\underline{\rule{200pt}{2pt}}

7 0
2 years ago
What is the value of the expression 86.24-79764
Fiesta28 [93]

Answer:

-79677.76

Step-by-step explanation:

Subtract the 79764 by using a calculator from the 86.24 and you should get a negative.

6 0
3 years ago
Read 2 more answers
Simplify 3 - (4x - 5) + 6.<br> A) 12x + 21 <br> B) 4x + 14 <br> C) 4x + 4 <br> D) -4x + 14
stepladder [879]

Answer:

D) -4x+14

Step-by-step explanation:

We are given with the expression

3 - (4x - 5) + 6

Here we are going to open the bracket at first step

as we have a negative sign in front of bracket the signs of the terms inside brackets will be reversed

3-4x+5+6

now we bring the like terms together

3+5+6 - 4x

Here 3, 5, 6 all are constant and hence like

14-4x

or

3 - (4x - 5) + 6= -4x+14

Hence our answer is -4x+14

6 0
3 years ago
Pls help me with my homework I need help
Mandarinka [93]

Answer:

need points luvk

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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