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NemiM [27]
3 years ago
15

2

48-3 \sqrt{x} 12+3\\ 27" alt="\sqrt{x} 48-3 \sqrt{x} 12+3\\ 27" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
djyliett [7]3 years ago
8 0

Answer:

This problem is not possible.

Step-by-step explanation:

Only functions and variables can have subscripts, or the number below the first 2. If we were to take that out, then we would get a line that starts at y = 8 and goes up on the x axis.

Hope that this helps!

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21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
Find the product. (a2 + 2a + 1)(a + 1) a. A2 + 3a + 2 b. A3 + 3a2 + 3a + 1 c. A3 + 2a 2 + a + 1 d. A3 + 3a2 + a + 1
olchik [2.2K]

 (a + 1)(a² + 2a + 1)

= a(a² + 2a + 1) + 1(a² + 2a + 1)

= a³ + 2a² + a   + a² + 2a + 1

= a³ + 3a² + 3a + 1

Answer: b

7 0
3 years ago
2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for
nadezda [96]

The question is incomplete:

1. A cosmetologist must double his/her salary before the employer con realize any profit from  his/her work,  Miss, Mead paid Miss, Adams $125,00 per week to start.

2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for  services if Miss. Mead is to realize $50.00 profit on her work? (Conditions on salary are the same  as in problem 1)  

ODS

a. $275.00 b. $325.00 c. $250.00 d. $300.00

Answer:

d. $300.00

Step-by-step explanation:

Given that a cosmetologist must double her salary before the employer can realize any profit from  his/her work, for Miss. Mead to realize $50.00 profit on her work, you would have to determine the amount that doubles the salary of the cosmetologist and add the $50 needed as profit:

Salary= $125*2=$250

$250+$50= $300

According to this, the answer is that for Mead to realize $50.00 profit on her work, Miss. Brown must take $300.

4 0
3 years ago
In a sociology class there are 1414 sociology majors and 1111 non-sociology majors. 33 students are randomly selected to present
saul85 [17]

Answer: 0.4065

Step-by-step explanation:

Given : In a sociology class there are 14 sociology majors and 11 non-sociology majors.

Total students = 14+11=25

Number of  students are randomly selected = 3

Then, the number of ways to select 3 students from 25 students :-

^{25}C_3=\dfrac{25!}{(25-3)!3!}=\dfrac{25\times24\times23\times22!}{22!3!}\\\\=2300

Number of ways to select  at least 2 of the 3 students re non-sociology majors :-

^{14}C_1\times^{11}C_2+^{14}C_0\times ^{11}C_{3}\\\\=(14)\times\dfrac{11!}{2!(11-2)!}+(1)\times\dfrac{11!}{3!(11-3)!}\\\\=(14)(11\times5)+\dfrac{11\times10\times9}{6}\\\\=770+165=935

The probability that at least 2 of the 3 students selected are non-sociology majors will be :-

\dfrac{935}{2300}=0.40652173913\approx0.4065

8 0
3 years ago
I need help with this because ima fail
Studentka2010 [4]

Answer:-αx-20=-14 --> \frac{-6}{x}

4=\frac{6}{a}×+5 --> a=-6

7+2ax=13---> a=\frac{3}{x}

Step-by-step explanation:

5 0
2 years ago
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