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amm1812
3 years ago
9

Sergio y Camila, decidieron juntar sus ahorros para comprar una cámara de video que cuesta $5 400.00. Si Sergio puso un medio de

l costo y Camila un tercio de éste, ¿cuánto dinero les falta y qué fracción representa?
Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

  • Amount remaining = $900
  • As fraction = 1/6

Step-by-step explanation:

Sergio brought a half of the $5,400 which is:

= 5,400 * 1/2

= $2,700

Camila brought a third of the cash which is:

= 5,400 * 1/3

= $1,800

The total amount remaining is:

= 5,400 - 2,700 - 1,800

= $900

As a fraction of the total this is:

= 900 / 5,400

= 1 / 6

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The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ &amp; Johnson​ (JNJ) stock for
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Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

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The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

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