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3 years ago

What is the equation for the line in slope-intercept form?

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Answer: y =4x

Step-by-step explanation: I think that's the answer can you tell me if it's correct

andreev551 [17]3 years ago

7 0

Answer:

y = -2x - 4

Step-by-step explanation:

this is for you k12 peps

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Shalnov [3]

Answer

The answer is 2,3,5

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3 years ago

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svp [43]

Answer:

Select the proportional relationship.

That is the only thing that is in the checkbox. It won't let you continue unless you get something.

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3 years ago

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Consider this expression: 4(5x - 7y). Enter an expression that shows the difference of exactly two terms that is equivalent to 4

Eddi Din [679]

Answer:

First you do what is inside the parentheses. 10 x 5 - 3. 50 - 3 =47. Then you multiply 47 x 5 = 235.

Step-by-step explanation:

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3 years ago

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Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

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3 years ago

In June, you bought 14.5 gallons of gasoline for $3.18 per gallon. The following February, you bought the same amount of gasolin

Nata [24]

Answer:

14.5 × 3.18 - 14.5 x 1.88

You paid $18.85 more in june than in February

Step-by-step explanation:

In order to find the answer to this question you will need to find how much you paid in June and how much you paid in February.

ex.14.5 x 3.18 - 14.5 x 1.88

To solve this you need to find the product of 14.5 x 3.18 and 14.5 x 1.88 and then subtract them from eachother.

ex.14.5 x 3.18 =46.11

14.5 x 1.88=27.26

46.11-27.26=18.85

3 0

3 years ago