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2 years ago

What is the equation for the line in slope-intercept form?

Mathematics

2 answers:

irinina [24]2 years ago

8 0

Answer: y =4x

Step-by-step explanation: I think that's the answer can you tell me if it's correct

andreev551 [17]2 years ago

7 0

Answer:

y = -2x - 4

Step-by-step explanation:

this is for you k12 peps

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Help me asap please & thank you.

Y_Kistochka [10]

Its the second choice down. x is an element of the intersection of B and C. A is not part of that, and since B and C overlap, it's the intersection, not the union (U).

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3 years ago

Can some one solve 2 I’ll give a crown

vitfil [10]

Answer:

Hi! The correct answer is 16!

Step-by-step explanation:

<em><u>~Use the formula (b/2)^2 in order to create a new term to complete the square~</u></em>

7 0

2 years ago

Read 2 more answers

The sum of a number and forty-six

ad-work [718]

$\textsf{Hey there!}$

$\mathsf{\star \ The\ sum\ of\ a\ number\ \&\ forty-six}$

$\frak{Let's\ lable\ the\ keypoints\ so\ it\ can\ be\ easier\ to\ solve}$

$\bullet \ \textsf{The word \bf{\underline{SUM}}}\textsf{\ means\ add/addition}}$

$\bullet\textsf{ \underline{"A number"} is an unknown number so we can lable it as \bf{x}}$

$\bullet\textsf{ \underline{forty-six} is 46}$

$\textsf{The sum (+) does in the middle while \underline{x} \& \underline{46} will either be on left/right}$

$- \ \textsf{We can say that x is on your left}$

$-\ \textsf{ + can be in your middle}$

$- \ \textsf{\& lastly 46 can be on your right}$

$\boxed{\textsf{Thus, your answer SHOULD LOOK like: \boxed{\huge\text{\bf{x + 46}}}}}\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

4 0

3 years ago

Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.

meriva

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}$

$\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}$

5 0

3 years ago

Help me with this problem please a and b

nadya68 [22]

(a) Compare your quadratic for h to the general quadratic ax² +bx +c. Perhaps you can see that ...
a = -16
b = 128
You use these numbers in the given formula to find the time when the ball is highest.
t = -b/(2a) = -128/(2(-16)) = 4 . . . . . . the time at which the ball is highest

(b) Evaluate the quadratic to find the height at t=4.
h = -16(4)² +128(4) +21
h = -256 +512 +21
h = 277
The maximum height of the ball is 277 ft.

5 0

3 years ago