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4 years ago

Write the unit rate and the rate 15 points scored in 4 quarters

1 answer:

3 0

You first divide both numbers by 4 to get one quarter which is the unit, and to get the rate, you divide 15 by 4 also. i got the unit rate is 3.75 points oer quarter.

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A bus traveled 300 miles in 6 hours. How many miles would the bus travel in 1 hour?

Oksi-84 [34.3K]

300 miles divided by 6 hours is a rate question. So the answer would be 50 miles per hour

7 0

3 years ago

Read 2 more answers

Solve the above equation for x.

Stella [2.4K]

Answer:

x=6

Step-by-step explanation:

(1/3x+2=4)x3

x+6=12

x=12-6

x=6

8 0

3 years ago

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If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

Ode to enchanted light Guiding Questions

Aleks04 [339]

You need to add what the lines are if you want them to be analysed for you^^

7 0

2 years ago

The discriminant of a quadratic equation is 40. What is the nature of solutions?

RSB [31]

Answer:

It means that the roots of the quadratic equation are real and distinct

Step-by-step explanation:

Here, given the discriminant of the quadratic equation, we want to find out the nature of the solutions.

Mathematically, we can use to determine the nature of the discriminant.

By it’s formula;

D = b^2 - 4ac

We can see that the given discriminant 40 is a positive value. What this means is that the quadratic equation has roots which are real and are distinct

4 0

4 years ago