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jolli1 [7]
3 years ago
5

In the question, "35 is what percent of 40?" what is the 35?

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

35 is the 'is' and 40 is the 'of'

Step-by-step explanation:

is/of = %/100

35/40 = x/100

cross-multiply to get:

40x = 3500

x = 3500/40

x = 87.5

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Ismael has a set of 5 solar panels and Ben has a set of 6 smaller solar panels. Each set of panels produce the same amount of en
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Answer:

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Step-by-step explanation:

If E is the amount of energy that each full set of panels produces, then ...

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5 0
3 years ago
Beatrice built about 1/3 of a sandcastle. Linda built 4/7 of the same castle. What fraction of the sandcastle did they build tog
wlad13 [49]

Answer    

Find out the what fraction of the sandcastle did they build together .

To prove

Let us assume that the fraction of the sandcastle  they build together be x .

As given

Beatrice\ built\ about\ \frac{1}{3}\ of\ a\ sandcastle.

Linda\ built\ \frac{4}{7}\ of\ the\ same\ castle.

Than the equation becomes

x = \frac{1}{3} +\frac{4}{7}

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solving

x = \frac{7 + 3\times4}{21}

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4 0
3 years ago
To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to th
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the height of the house is 408ft .

<u>Step-by-step explanation:</u>

Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find  What is the height of the house . Let's find out:

Let  y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.

Distance of house from point A( initial point ) = x ft

Distance of house from point B( when she traveled 200 ft towards street  = x-200 ft

Now , According to question these scenarios are of right angle triangle as

At point A

⇒ Tan32 =\frac{Perpendicular}{Base}= \frac{y}{x}

⇒ Tan32 = \frac{y}{x}

⇒ y=x(Tan32 )       ..................(1)

Also , At point B

⇒ Tan42 = \frac{y}{x-200}

⇒ y=(x-200)(Tan42)     ..............(2)

Equating both equations:

⇒ (x-200)(Tan42) = x(Tan32)

⇒ x(Tan42-Tan32)=Tan42(200)

⇒ x=\frac{Tan42(200)}{(Tan42-Tan32)}

⇒ x=653ft

Putting  x=653ft in  y=x(Tan32 )  we get:

⇒  y=x(Tan32 )    

⇒  y=653(Tan32 )

⇒  y=408ft

Therefore , the height of the house is 408ft .

4 0
3 years ago
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