R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
Answer:
Solutions are -10 and 26
Step-by-step explanation:
( - the abolute sign I'm using
( x - 8 ) + 2 = 20
( x - 8 ) = 18
x - 8 = 18 (postive case)
x - 8 + 8 = 18 + 8
x = 26
( x - 8 ) = 18
x - 8 = -18 (negative case)
x - 8 + 8 = -18 + 8
x = -10
2/7 as a fraction rounds to 0.3
0.3 * 3 = 0.9
3 x 2/7 is less than 3
The answer is 43 because it is half of 86 which is the radius
Answer:
Step-by-step explanation:
