Question

Mr. Lyle made a round trip between two cities that were 450 kilometers apart. On the return trip, he increased his average of rate travel by 5 km/h and made the trip in one hour less. Find his rate for each direction.

Answer 1

Answer:

45 km/h

50 km/h

Step-by-step explanation:

Distance traveled in one way = 450 km

Let x = Velocity when he was going to his destination in km/h

He traveled 5 km/h faster when he returned so his velocity was $x+5$

It took him 1 hour less when he returned so

$\dfrac{450}{x}-\dfrac{450}{x+5}=1\\\Rightarrow x^2+5x-2250=0\\\Rightarrow x=\frac{-5\pm \sqrt{5^2-4\times 1\times \left(-2250\right)}}{2\times 1}\\\Rightarrow x=45,-50$

So, velocity while going to his destination is 45 km/h

While returning his velocity was 45+5 = 50 km/h.