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Lerok [7]
3 years ago
5

Use substitution to solve the system 5x-3y=23 2x+y=7

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0
Because "y" is + in <span>2x+y=7, let's subtract 2x from both sides and end up with an expression for y:  y = 7 - 2x.  Substituting this into 5x - 3y = 23, 

5x - 3(7 - 2x) = 23.  Multiply out -3(7 - 2x):

5x - 21 + 6x = 23.  Combining 5x and 6x, 11x - 21 = 23, or 11x = 44.

Thus, x = 4.  Since y = 7 - 2x, subst. x = 4 results in the value of y:

y = 7 - 2(4) = 7 - 8 = -1.

The solution is (4,-1).</span>
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2: Write out a system of equations that has infinite solutions. Explain why it has infinite
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Below!

Explanation:

A system of equations with infinite solutions defines that both the equations are identical and are overlapping when the lines are graphed. An example could be y = 5x + 9 and y = 5x + 9. These sets of equations have infinite solutions because they are the same and when graphed, they overlap.

Hoped this helped!

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2 years ago
An engineer was supposed to draw a line exactly 7/10 centimeters long. An error was made, and he drew the line 9/10 centimeters
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Answer:

2/10 or 1/5 if you want it simplified

Step-by-step explanation:

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7 0
2 years ago
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Let a,b,c ∈ Z. Define the highest common factor hcf(a,b,c) to be the largest positive integer that divides a,b and c. Prove that
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3 years ago
An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th
antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c  ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200 \times a + 100 \times c = 2100

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

<h3>c = 5</h3>

Thus the cost of children’s ticket is $ 5

6 0
3 years ago
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