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3 years ago

Graph the equations y=x-2 and x + y = 6 on the grid provided.

Mathematics

1 answer:

Colt1911 [192]3 years ago

7 0

Formulas:

y=x-2

y=-1x+6

You'll basically just graph these which you said you can do, and if you don't want to, just input these formulas in Desmos Graphing Calculator, and the point that they intersect is your answer for the point of intersection

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3 years ago

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(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

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$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

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$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

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3 years ago

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Salsk061 [2.6K]

Answer:

BADC

Step-by-step explanation:

-4x + 7 $\geq$ 27 Subtract 7

-4x $\geq$ 20 Divide both sides by -4

x $\leq$ -5 B

3x - 10 < -25 Add 10

3x < -15 Divide by 3

x < -5 A

5(x - 2) > -15 Use distributive property

5x - 10 > -15 Add 10

5x > -5 Divide by 5

x > -1 D

x - 9 < -10 Add 9

x < -1 C

8 0

3 years ago