HELP ME PLEASE SOMEBODY

Jocelyn gave the cashier $50 to pay for 3 shirts. The cashier gave her $5.03 in change. Each shirt cost the same amount. W

Goryan [66]

Answer:

14.9

Step-by-step explanation:

50-5.03 = 44.97

44.97 ÷ 3 = 14.99

8 0

2 years ago

Could someone help me out ill mark brainliest

zlopas [31]

Step-by-step explanation:

1. The first graph has a negative slope (increases to the left) and has a y-intercept of 3. So, the equation of the line would be y = -2x + 3.

2. The second graph has a positive slope (increases to the right) and has a y-intercept of -3. Therefore, the equation of the line would be y = 2x - 3.

3. The third graph has a negative slope and has a y-intercept of -3. So, we can say that the equation of the line would be y = -2x - 3.

4. The fourth graph has a positive slope and a y-intercept of 3. Therefore, the equation of the line would be y = 2x + 3.

8 0

3 years ago

Read 2 more answers

A study of peach trees found that the average number of peaches per tree was 725. The standard deviation of the population is 70

TEA [102]

Answer:

She needs to sample 189 trees.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation of the population is 70 peaches per tree.

This means that $\sigma = 70$

How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree?

She needs to sample n trees.

n is found when M = 10. So

$M = z\frac{\sigma}{\sqrt{n}}$

$10 = 1.96\frac{70}{\sqrt{n}}$

$10\sqrt{n} = 1.96*70$

Dividing both sides by 10:

$\sqrt{n} = 1.96*7$

$(\sqrt{n})^2 = (1.96*7)^2$

$n = 188.2$

Rounding up:

She needs to sample 189 trees.

3 0

3 years ago

F(x) = 2x - 1, g(x) = 3x, h(x) = x2 + 1<br> Compute the following:<br> h(f(9))

Tamiku [17]

H(2)=5-F+g(2)=(f • h)(2)=f

6 0

3 years ago

If p is a polynomial show that lim x→ap(x)=p(a

Lostsunrise [7]

Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

Solution. Notice that

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

= 2|x|^3 + 5|x|^2 + |x| + 2

< 2(2)^3 + 5(2)^2 + (2) + 2

= 40

Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

3 0

3 years ago