Answer:
We just need to evaluate and get f(2i)=0, f(-2i)=0.
Step-by-step explanation:
Since 
, then 
, and we can apply this when we evaluate 
for 2i and -2i.
First we have:
Which shows that 2i is a zero of f(x).
Then we have:
Which shows that -2i is a zero of f(x).
Answer:
41
Step-by-step explanation:
Answer:
-250
Step-by-step explanation:
I don't know for sure but I hope it's correct.
For this question you can say:
-8 -11q = -9q +6
so now you can add +9q on both sides and +8 on both sides of the equation:
-11q + 9q = 8 + 6
-2q = 14
q = 14/-2
q = -7 :)))
I hope this is helpful
have a nice day
Answer:
The answer is C=6p3 + 29p2 + 22p – 21
Step-by-step explanation:
To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
= 6p³ + 8p² - 6p + 21p² + 28p - 21
= 6p³ + 8p² + 21p² + 28p - 6p -21
= 6p³ + 29p² + 22p - 21
Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21
