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Sonja [21]
3 years ago
14

I WILL GIVE OUT BRAINELIST Quadratic functions g(x) and h(x) are graphed on the same coordinate grid. The vertex of the graph of

h(x) is 12 units above the vertex of the graph of g(x) .
Which pair of functions could have been used to create the graphs of g(x) and h(x)?

h(x)=(x+12)2 and ​g(x)=x2​

h(x)=x2−12 and g(x)=x2

h(x)=x2+12 and ​g(x)=x2​

h(x)=(x−12)2 and ​g(x)=x2
Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

  h(x)=(x-12)2 and g(x)=2

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Perpendicular to y = 2x – 6<br> and passing through (4,3)
ladessa [460]

Answer:

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Step-by-step explanation:

y = 2x – 6        slope = 2

Perpendicular line slope = -1/2

for (4 , 3)      y = mx + b       y = 3, x = 4,   m = -1/2

b = y - mx = 3 - (-1/2) x 4 = 5

equation: y = - 1/2x + 5

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2 years ago
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Answer:

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3 years ago
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The solution to a system of two linear equations is (4, -3). One equation has a slope of 4. The slope of the other line is the n
astraxan [27]

Answer:

Hello,

First equation is false

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Step-by-step explanation:

1)

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(4,-3) is not a point of the line y=1/4x-2 since

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I have written that because it is difficult for me to understand

"the negative reciprocal of the slope of the first"

the negative reciprocal of 4 should be -1/4.

Equation y=1/4x-2 is false.

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GalinKa [24]

Answer:

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Step-by-step explanation:

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you are working with diameter

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Diano4ka-milaya [45]

Answer:

20%

I hope this is good enough:

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