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LenaWriter [7]
3 years ago
12

Use a truth table to verify the first De Morgan law (p ∧ q)’ ≡ p’ ∨ q’.

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0

Answer:

(p ∧ q)’ ≡ p’ ∨ q’

Step-by-step explanation:

First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.

p ∧    q

t t t

t f f

f f t

f f f

next step is getting the opposite

(p∧q)'

    <em>f</em>

<em>     t</em>

<em>     t</em>

<em>     t</em>

Then we get p' V q', V is true (t) when the first or the second is true.

p' V  q'

f  <em>f</em>  f

f  <em>t</em>  t

t  <em>t</em>  f

t  <em>t</em>  t

Let's compare them, ≡ is true if the first is equal to the second one.

(p∧q)'   ≡     (p' V q')

    <em>f              f </em>

<em>     t              t</em>

<em>     t              t</em>

<em>     t              t</em>

Both are true, so

(p ∧ q)’ ≡ p’ ∨ q’

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