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garik1379 [7]
2 years ago
7

Drag all of the division problems that have an estimated quotient of 12 into the box.

Mathematics
1 answer:
Mars2501 [29]2 years ago
4 0
Answer:
Option 5 & 6

Step by Step Explanation:
8 / 0.95 = 8.4 ( wrong )
18 / 2.2 = 8.18 ( wrong )
47.6 / 3.9 = 16.41 ( wrong )
10.6 / 1.89 = 5.6 ( wrong )
71.9 / 6.5 = 11.061 ( correct )
123.4 / 9.2 = 13.41 ( correct )
157.4 / 16.4 = 9.59 ( wrong )



hope this helps! please give brainliest and thanks!!!
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Find the area of the trapazoid for me please :)
Doss [256]

Answer:

A = 14 m^2

Step-by-step explanation:

The area of a trapezoid is found by

A = 1/2 (b1+b2) *h  where b is the length of the bases and h is the height

A = 1/2 (2+5) *4

A = 1/2(7)4

A = 14 m^2

6 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
Find the measure of angel 3
Elena-2011 [213]

Answer:

100

Step-by-step explanation:

Remark

If two opposite arcs are given by being opposite vertically opposite angles, then the value of both the vertically opposite angles are equal to

Vertically opposite angle = 1/2 (arc1 + arc2)

Givens

Arc1 = 60

Arc2 = 100

Solution

The red dot angle = 1/2 (60 + 100)

The red dot angle = 1/2(160)

The red dot angle = 80

Because the red dot angle and <3 are on the same line with the same common point, they are supplementary.

<3 and red dot = 180

<3 + 80 = 180                          Subtract 80 from both sides

<3 = 180 - 80

<3 = 100

8 0
3 years ago
the slide at the playground has a height of 6 feet.The base of the slide measured on the ground is 8 feet.what is the length of
NemiM [27]
The formula for finding the length is
{a}^{2}  +  {b}^{2} = {c}^{2}
All we have to do is plug in the numbers.

{6}^{2}  +  {8}^{2}  =  {c}^{2}
36 + 64 = 100

Since 100 =
{c}^{2}
we have to find the square root.

\sqrt{100}  = 10

The length of the slide is 10 feet.

6 0
3 years ago
#15 i
MA_775_DIABLO [31]

The inequality which represents the missing dimension x is x≥1.6 or x≥8 / 5.

Given that the area is greater than or equal to 8 square feet and image is attached below.

We want to find the missing inequality x in the form of inequality.

The figure is assumed to be a right triangle with Root = x and perpendicular = 10ft.

As we know the area of ​​a triangle is half the product of the base and the height.

First of all, we will find the area of ​​the triangle by substituting the given values ​​we get

Area=(1/2)×Base×height

Area=(1/2)×x×10

Area=5x      ......(1)

Assume that this area is greater than or equal to 8 square feet.

That means Area≥8ft²      ......(2)

Now we will balance equation (1) and equation (2), we get

5x≥8ft²

Furthermore, they we will divide both sides by 5 we get

(5x)/5≥8/5

x≥8/5

x≥1.6

Therefore, the inequality represents the missing size x when the area is larger or equal to 8 square feet is x ≥1.6ft².

Learn more about the dimension from here brainly.com/question/13271352

#SPJ9

4 0
1 year ago
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