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Bogdan [553]
3 years ago
5

I need help graphing and answering this, please answer I really need help!

Mathematics
1 answer:
Llana [10]3 years ago
8 0
The equation is proportional and the slope is 2/7. y is 0 so you go 2 right and 7 up, keep repeating this. if you want it to go down to be a full line, start at y and go 2 left and 7 down
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dangina [55]
C:
6*2 = 2.5c
c = 4.8

b:
Cannot be solved until the measure of one other angle in the X is added.
6 0
3 years ago
Please help me!!!!!!!!!
Serga [27]

Answer:

Step-by-step explanation:

I assume we are finding the slope of the line.  It is positive since it runs from the lower left to the upper right, so forget B and D.  Since slope is defined as rise over run, in order to get from one point on the line that goes through right where the grids meet to another point that goes through right where the grids meet we count up 1 unit and then to the right 6 units.  This is a slope of 1/6.

5 0
3 years ago
Two blocks of wood are shaped as right rectangular prisms. The smaller block has a length of 9 cm, a width of 3 cm, and a height
solmaris [256]
1512 I believe! :) I would double all the dimensions first, then multiply them all together. 
3 0
3 years ago
Read 2 more answers
Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg
Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) <u>Optimal solution</u>: 40.000 units of R and 10.000 of PC = $17.000

c) <u>Slack variables</u>: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) <u>Binding Constaints</u>:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is  

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.  

3 0
3 years ago
Rectangle area w algebra<br> step by step explanation please :)
Natalija [7]

We know that the area is 20.

Since 20 is a small number: lets list out possible combinations of lengths and widths.

1 * 20

2 * 10

4 * 5

L = 7 + 3w

lets see which on makes sense.

L = 7 + 3w

20 = w7 + 3w^2

3w^2 + 7w -20 = 0

(3w - 10)(w - 2)

w can equal 10/3 or 2.

So the dimensions: are Width = 2 Length = 10

8 0
3 years ago
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