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miss Akunina [59]
3 years ago
14

Anyone know how to solve this? help!

Mathematics
1 answer:
oee [108]3 years ago
4 0
Okay I did the work and I think it’s either answer a or b but goodluck sorry

But I still don’t understand this.
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Order these numbers in ASCENDING order. 0.7 2/3 6/8 65%​
Kryger [21]

Answer:

65%, 2/3, 0.7, 6/8

Step-by-step explanation:

4 0
3 years ago
Hello im in 8th grade and I need to get my grades up so anyone know the answer to
jolli1 [7]

Answer:

x = 3

Step-by-step explanation:

12x = 36

simply 12 will go to the other side and switches to the opposite sign for example + will be -

× will br ÷

so 36 ÷ 12 =3

x = 3

4 0
3 years ago
8x+3y= 28 and 7x-3y=2<br>solve for x and y simontaniasly using elimination ​
EleoNora [17]

Answer:

x=2, y=4

Step-by-step explanation:

When using elimination, the objective is to elimate one variable. In this case, we see that "y" can easily be eliminated by adding the two equations together since you will get 3y + (-3y) which will eliminate y because the value would become 0, letting us solve for x.

\left \{ {{8x+3y=28} \atop {7x-3y=2}} \right. +\\

Then we get

15x =30, because the y's will eliminated, and 8x+7x is 15x, and 28+2 is 30.

Then divide by 15 on both sides and you get x=2

If x=2, then we can substitute that value into any of the previous given equations and find the value of y.

8×2 +3y = 28

16+3y=28

3y=12

y=4

So the answer to your system of equations would be x=2, and y=4

You can substitute the answers we found to see that they satisfy the equation.

Hope this helped.

6 0
3 years ago
The angle measures of a triangle are shown in the diagram.
STALIN [3.7K]

Answer:

Step-by-step explanation:

B

5 0
3 years ago
Express this number in standard form. 2.456 times 10^11 ​​
Varvara68 [4.7K]
Its 2.456*10=11

hope this helps and please rate below and also i am great with helping people who are going through a lot like family or school or friendship problems so if u want help or tips about those things or even depression feel free to ask me through message and i will see what i can do to help you. :)
5 0
3 years ago
Read 2 more answers
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