∠LQK+∠GQL=90º
Therefore:
(4n-15)+(3n)=90
7n=90+15
7n=105
n=105/7
n=15
∠LQK=4n-15=4(15)-15=60-15=45
Answer: ∠LQK=45º
(5,0) if there is no y then it is a 0
If a polynomial with real coefficient has a complex zero, the conjugate of that number will be a zero as well.
So, if 4-6i is a zero, 4+6i will be a zero as well
If -2+11i is a zero, -2-11i will be a zero as well
So, the zeroes are
