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Deffense [45]
3 years ago
8

Please help me asap​

Mathematics
2 answers:
Paraphin [41]3 years ago
5 0

Answer:

1) B (66)

2) A (-36)

3) A (10)

4) B (1)

Step-by-step explanation:

Just solve the equation by using inverse operations

Andre45 [30]3 years ago
4 0
(1) 66
(2) -36
(3) 10
(4) 1
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Find the solution of this system of equations<br> 4x - 5y = -12<br> -X + 5y = 18
Natalka [10]

4x - 5y = -12

-x + 5y = 18

Add the equations together:

4x + -x = 3x

-5y + 5y = 0

-12 + 18 = 6

So now you have:

3x = 6

Divide both sides by 3:

X = 2

Now you have the value of x, replace x with 2 in one of the equations and solve for y:

4(2) -5y = -12

8 -5y = -12

Subtract 8 from both sides:

-5y = -20

Divide both sides by -5:

Y = 4

The solution is x = 2 and y = 4 which is written as (2,4)

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3 years ago
Solve −2(n+3)−4=8 . The solution is n= .
Anton [14]

Answer:

n= -9

Step-by-step explanation:

Simplifying

-2(n + 3) + -4 = 8

Reorder the terms:

-2(3 + n) + -4 = 8

(3 * -2 + n * -2) + -4 = 8

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Reorder the terms:

-6 + -4 + -2n = 8

Combine like terms: -6 + -4 = -10

-10 + -2n = 8

Solving

-10 + -2n = 8

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + -2n = 8 + 10

Combine like terms: -10 + 10 = 0

0 + -2n = 8 + 10

-2n = 8 + 10

Combine like terms: 8 + 10 = 18

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Simplifying

n = -9

3 0
4 years ago
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cupoosta [38]

Answer:

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4 0
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1/3÷100 will the answer be smaller than 1 close to 1 or much greater than 1
Radda [10]

Answer:

It will be smaller than one

Step-by-step explanation:

because i said so

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3 years ago
Let mu denote the true average number of minutes of a television commercial. Suppose the hypothesis H0: mu = 2.1 versus Ha: mu &
natka813 [3]

Answer:

A. T > 2.539

Step-by-step explanation:

We have a hypothesis test of the mean, with unknown population standard deviation.

The hypothesis are:

H_0: \mu = 2.1 \\\\H_a: \mu > 2.1

From the hypothesis we can see that the test is right-tailed, so the critical value of t should be a positive value.

The degrees of freedom can be calculated as:

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7 0
3 years ago
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