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svetoff [14.1K]
3 years ago
7

7) The negative-feedback system of the endocrine system works much like a ______

Chemistry
1 answer:
stira [4]3 years ago
7 0

Answer:  Most of the hormones released by endocrine system are regulated by negative feedback mechanism.

- Negative feedback mechanism functions to reduce the intensity of original stimulus in order to maintain homeostasis.

Explanation:

When blood calcium levels are decreased, parathyroid gland releases parathyroid hormone (PTH).

PTH acts on bone and stimulate bone resorption by promoting osteoclastic activity. It stimulates reabsorption of calcium in kidneys. PTH promotes calcitriol synthesis that acts on small intestine to increase calcium absorption.

Action of PTH increases blood calcium levels.

When blood calcium levels are increased, thyroid gland releases hormone calcitonin.

Calcitonin opposes PTH and acts to deposit calcium in the bone.

Calcitonin acts on osteoblasts and promote increase in bone mass.

Action of calcitonin decreases blood calcium levels.

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Mass and volume can be used to describe what general property?
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3 dimensional figure
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3 years ago
What is the name of group 6a,7a,and 8a
vodka [1.7K]

Answer:

Refering to Chemistry,

The Group names are:

Group 6A: Chalcogens

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Group 8A: Noble/Inert Gasses

8 0
4 years ago
A solution of is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at 477 nm, what is t
inn [45]

Answer:

The concentration of the solution is 1.068×10⁻⁴M

Explanation:

Hello,

To find the concentration of the solution, we'll have to use Beer-Lambert law which states absorption is directly proportional to the concentration of the solution.

Beer-Lambert law = A = εCL

A = absorption = 2 - log₁₀%T = 2 - log₁₀(34)

A = 2 - 1.5314 = 0.47

A = 0.47

ε = molar absorption coefficient = 4400

C = concentration of the solution

L = path length = 1cm

A = εcl

C = A / εl

C = 0.47 / 4400 × 1

C = 1.068×10⁻⁴M

The concentration of the solution is 1.068×10⁻⁴M

3 0
4 years ago
What usually happens to the outer electrons of metallic atoms when they combine chemically with nonmetallic atoms?
aleksandr82 [10.1K]
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7 0
3 years ago
In the first 15.0 s of the reaction, 1.7×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.440 L . What is the
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Answer:

Rate=2.57x10^{-3}\frac{M}{s}

Explanation:

Hello,

In this case, for the reaction:

2N_2O(g) \rightarrow  2N_2(g)+O_2(g)

We can easily compute the average rate by firstly computing the final concentration of oxygen:

[O_2]=\frac{0.017mol}{0.440L}=0.0386M

Then, we compute it by using the given interval of time: from 0 seconds to 15.0 seconds and concentration: from 0 M to 0.0386M as oxygen is being formed:

Rate=\frac{0.0386M-0M}{15.0s-0s}\\ \\Rate=2.57x10^{-3}\frac{M}{s}

Regards.

8 0
4 years ago
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