Answer:
2000 mL
Explanation:
We have the following data:
Initial volume: V₁ = 1000 mL
Initial temperature: T₁ = -86°C + 273 = 187 K
Final temperature: T₂= 101°C + 273 = 374 K
According to Charles' law, as the temperature of a gas is increased at constant pressure, the volume is increased. That is expressed mathematically as:
V₁/T₁ = V₂/T₂
Thus, we calculate the final volume V₂ as follows:
V₂ = V₁/T₁ x T₂ = (1000 mL)/187 K x 374 K = 2000 mL
Therefore, the final volume is 2000 mL.
Answer: The correct answer is A
Explanation:
On addition of the ammonium nitrate to 50 ml of water the temperature decreases which means that reaction between the ammonium nitrate and water is an endothermic reaction.The value of is positive for an endothermic reactions.
Entropy is a degree of randomness of the system.
On addition of the ammonium nitrate to water ammonium nitrate break down into ions which means that entropy is increased.
(Gibb's free energy)
Since, ammonium nitrate is getting dissolved in water which means that this reaction is spontaneous and of spontaneous reaction is negative that is:
Answer:
a) Superficial fluid
b) 5.9*10^-2 atm
c) Gas
d) Liquid
e) Solid
Explanation:
a) At temperatures above 405.5 K and pressures above 111.5 atm, NH3 is a superficial fluid because liquid and gases does not exit at temperature and pressure greater than 405.5 K and 111.5 atm
b) NH3 does not exist as a liquid at pressures below 5.9*10^-2 atm , That is below the triple point there is existence of liquid
c) NH3 is a Gas at 5.90×10^-2 atm and 249.5 K.
d) NH3 is a Liquid at 1.00 atm and 236.0 K. because pressure and temperature ( standard ) is between the given normal melting and boiling point
e) NH3 is a solid at 24.6 atm and 185.6 K . because the pressure here is more than that of triple point while the temperature is lesser
Answer:
49.95 g of HCl
Explanation:
Let's formulate the chemical equation involved in the process:
Ca(OH)2 + 2 HCl → CaCl2 + 2 H2O
This means that we need 1 mole of Calcium hydroxide to neutralize 2 moles of hydrochloric acid. From this, we calculate the quantity of HCl moles that would be neutralized by 0.685 moles of Ca(OH)2
1 mole Ca(OH)2 ---- 2 moles HCl
0.685 moles Ca(OH)2 ---- x = 1.37 moles HCl
Now that we know the quantity of HCl moles that would react, let's calculate the quantity of grams this moles represent:
1 mole of HCl ---- 36.46094 g
1.37 moles ------ x = 49.95 g of HCl
Nope the atomic mass of copper roughly 63,546 atomic mass units