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1 year ago

What is the position of the earth, moon, and sun during a new moon?

2 answers:

6 0

Answer:When the Moon is between the Earth and the Sun, the bright side of the Moon is facing away from the Earth, and we have a New Moon.

Explanation:

Reika [66]1 year ago

4 0

Answer:

In the case of a New Moon, the Moon is between Earth and the Sun, so the side of the Moon facing the Sun isn't facing us. We can't see any portion of the lit-up Moon during this phase. (When the Sun and Moon exactly line up, as viewed from Earth, we get a special experience known as a solar eclipse

Explanation:

good luck hope this helps

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A gas is at a pressure of 3.70 atm. What is this pressure in kilopascals?

Yanka [14]

Answer:
= 374.90 kPa

Calculation:
As we know atm and kiloPascal are related to each other as,

1 atm = 101.325 kPa
So,
3.70 atm = X
Solving for X,
X = (3.70 atm × 101.325 kPa) ÷ 1 atm

X = 374.90 kPa

7 0

3 years ago

I in the blanks.<br>The solid substance left on the filter paper is called

horsena [70]

Explanation:

the solid substance which left on the filter paper is called Residue

3 0

2 years ago

The ph of a solution prepared by mixing 45.0 ml of 0.183 m koh and 35.0 ml of 0.145 m hcl is ________.

Naddika [18.5K]

Answer:

12.6.

Explanation:

We should calculate the no. of millimoles of KOH and HCl:

no. of millimoles of KOH = (MV)KOH = (0.183 M)(45.0 mL) = 8.235 mmol.

no. of millimoles of HCl = (MV)HCl = (0.145 M)(35.0 mL) = 5.075 mmol.

It is clear that the no. of millimoles of KOH is higher than that of HCl:

So,

[OH⁻] = [(no. of millimoles of KOH) - (no. of millimoles of HCl)] / (V total) = (8.235 mmol - 5.075 mmol) / (80.0 mL) = 0.395 M.

∵ pOH = -log[OH⁻]

∴ pOH = -log(0.395 M) = 1.4.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.4 = 12.6.

4 0

2 years ago

Which of the following is possible for aluminum to have a full outer shell?

lesya [120]

B. Three are lost creating Al+3. Because atoms have and equal amount of Protons and Electons when neutral losing 3 electrons will create a positive Al ion Al+3

8 0

3 years ago

Read 2 more answers

How many litres (L) of oxygen at STP can be obtained from 110 g of potassium chlorate? [R=0.0821 L.atm/K.mol]

lisabon 2012 [21]

Balance the equation first:

2 KClO3 (s) ---> 2 KCl (s) + 3 O2 (g)

Moles of KClO3 = 110 / 122.5 = 0.89

Following the balanced chemical equation:
We can say moles of O2 produce = $\frac{3}{2}$ x moles of KClO3

So, O2 = (3 / 2) x 0.89

= 1.34 moles

So, Volume at STP = nRT / P

T = <span>273.15 K
P = 1 atm

So, V = (1.34 x 0.0821 x 273.15) / 1 = 30.2 L</span>

3 0

3 years ago