What is the position of the earth, moon, and sun during a new moon?

2 answers:

6 0

Answer:When the Moon is between the Earth and the Sun, the bright side of the Moon is facing away from the Earth, and we have a New Moon.

Explanation:

Reika [66]2 years ago

4 0

Answer:

In the case of a New Moon, the Moon is between Earth and the Sun, so the side of the Moon facing the Sun isn't facing us. We can't see any portion of the lit-up Moon during this phase. (When the Sun and Moon exactly line up, as viewed from Earth, we get a special experience known as a solar eclipse

Explanation:

good luck hope this helps

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lara [203]

Answer:

Balanced forces are equal in size and opposite in direction. When forces are balanced, there is no change in motion. In one of your situations in the last section, you pushed or pulled on an object from opposite directions but with the same force. You observed that the object did not move.

Explanation:

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7 0

2 years ago

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Which of the following is a mineral? coal ling glass brick salt

natta225 [31]

Answer:

Salt, (Coal is a mineral but barely, but Salt is your best answer), (And if it's multiple choice its Salt and Coal)

Explanation:

Salt (NaCl), sodium chloride, mineral substance of great importance to human and animal health, as well as to industry. The mineral form halite, or rock salt, is sometimes called common salt to distinguish it from a class of chemical compounds called salts.

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2 years ago

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The tabulated data were collected for this reaction:

erastovalidia [21]

Answer:

ai) Rate law, $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

aii) Rate constant, k = 1.25

b) Overall order of reaction = 1.5

Explanation:

Equation of Reaction:

$CH_{3} Cl (g) + 3 Cl_2 (g) \rightarrow CCl_4 (g) + 3 HCl (g)$

If $A + B \rightarrow C + D$ , the rate of backward reaction is given by:

$Rate = k [A]^{a} [B]^{b}\\k = \frac{Rate}{ [A]^{a} [B]^{b}}\\k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$

k is constant for all the stages

Using the information provided in lines 1 and 2 of the table:

$0.014 / [0.05]^a [0.05]^b = 00.029/ [0.100]^a [0.05]^b\\0.014 / [0.05]^a [0.05]^b = 00.029/ [2*0.05]^a [0.05]^b\\0.014 / = 0.029/ 2^a\\2^a = 2.07\\a = 1$

Using the information provided in lines 3 and 4 of the table and insering the value of a:

$0.041 / [0.100]^a [0.100]^b = 0.115 / [0.200]^a [0.200]^b\\0.041 / [0.100]^a [0.100]^b = 0.115 / [2 * 0.100]^a [2 * 0.100]^b\\$

$0.041 = 0.115 / [2 ]^a [2]^b\\ \[[2 ]^a [2]^b = 0.115/0.041\\ \[[2 ]^a [2]^b = 2.80\\\[[2 ]^1 [2]^b = 2.80\\\[[2]^b = 1.40\\b = \frac{ln 1.4}{ln 2} \\b = 0.5$