In a rate law, the rate constant, k, depends only on the temperature.
If the temperature is constant, the rate constant is a constant.
The answer is phosphorus-32.
We know that the atom contains <span>15 protons, 15 electrons, and 17 neutrons.
To conclude of which element this radionuclide is, we need to know an atomic number of the element. The atomic number of the element is the number of proton in the nucleus of the atom. If the number of protons is 15, then the atomic number is 15. The element with atomic number 15 is phosphorus (according to the periodic table).
To conclude which phosphorus isotope this radionuclide is we need to know the mass number of the element. The mass number of the element is the sum of the number of protons and number of neutrons in the nucleus of the atom. If the number of protons is 15 and the number of neutrons is 17, then the mass number is 17 + 15 = 32.
Thus, this radionuclide is phosphorus-32.</span>
Answer:
A) ΔG° = -3,80x10⁵ kJ
B) E° = 2,85V
Explanation:
A) It is possible to answer this problem using the standard ΔG's of formation. For the reaction:
Mg(s) + Fe²⁺(aq) → Mg²⁺(aq) + Fe(s)
The ΔG° of reaction is:
ΔG° = ΔGFe(s) + ΔGMg²⁺(aq) - (ΔGFe²⁺(aq) + ΔGMg(s) <em>(1)</em>
Where:
ΔGFe(s): 0kJ
ΔGMg²⁺(aq): -458,8 kJ
ΔGFe²⁺(aq): -78,9 kJ
ΔGMg(s): 0kJ
Replacing in (1):
ΔG° = 0kJ -458,8kJ - (-78,9kJ + okJ)
<em>ΔG° = -3,80x10² kJ ≡ -3,80x10⁵ kJ</em>
B) For the reaction:
X(s) + 2Y⁺(aq) → X²⁺(aq) + 2Y(s)
ΔG° = ΔH° - (T×ΔS°)
ΔG° = -629000J - (298,15K×-263J/K)
ΔG° = -550587J
As ΔG° = - n×F×E⁰
Where n are electrons involved in the reaction (<em>2mol</em>), F is faraday constant (<em>96485 J/Vmol</em>) And E° is the standard cell potential
Replacing:
-550587J = - 2mol×96485J/Vmol×E⁰
<em>E° = 2,85V</em>
I hope it helps!
Answer:
I really dont know i just guessed :(
Explanation:
Pretty sure it's the Precambrian.
