Answer:
b
Step-by-step explanation:
because the equation is equal to bn times m
Answer:
Step-by-step explanation:
Let X denote the amount of time spending exercise in a given week
Given that X normal (3.8, (0.8)²)
Thus we know that
i)P [ amount of time less than two hour ]
= P[x < 2]
ii)
= P[z > 2.25] ∴ symmetric
= P[0 ≤ z ≤ ∞] - P[0 ≤ z ≤ 2.25]
= 0.5 - 0.48778
= 0.0122
iii)
P[2 < x < 4]
Answer:
B.
Step-by-step explanation:
a function is continuous, if the functional values are the same at the "connection" points of the various segments (and the segments themselves are continuous).
"continuous" simply means that the graph of the function is a continuous line without any "rips". it can have corners and such, but no "interruptions".
specifically it means : for every possible y value in the defined range of the function there is an x value that causes this y.
all defined segments are continuous functions.
so, let's look at
A. the first connection point is x=-2.
-2 + 6 = 0.5×(-2)²
4 = 0.5×4 = 2
4 = 2 is wrong. => here, at this point, the function "rips" apart and is not continuous.
B. x=-2
-2 + 4 = 0.5×(-2)²
2 = 2 is correct. continuous at this point.
second connection point x=4
0.5×4² = 20 - 3×4
0.5×16 = 20 - 12
8 = 8 is correct. continuous at this point
C. x=-2
-2 - 2 = 0.5×(-2)²
-4 = 2 is wrong. not continuous
D. x=-2
-2 + 4 = 0.5×(-2)²
2 = 2 is correct. continuous here.
now for x=4
4 + 4 = 25 - 3×4
8 = 25 - 12 = 13
8 = 13 is wrong. not continuous.
It’s the first one.............
Answer: B. 5/13
This is the same as writing
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Reason:
We have two given sides of this right triangle. Use the pythagorean theorem to find the missing side.
a = 5 and b = 12 are the two known legs; c is the unknown hypotenuse
The hypotenuse is exactly 13 units long. This is a 5-12-13 right triangle.
Now we can compute sine of theta
This points us to choice B as the final answer.
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Extra Info (optional)
- 5/12 is the value of tan(theta) since it's opposite/adjacent
- 12/5 is the value of cot(theta), the reciprocal of tangent
- 12/13 is the value of cos(theta), because cos = adjacent/hypotenuse