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natta225 [31]
3 years ago
10

Help please my moms going to kill me if I don’t get this right

Mathematics
1 answer:
iragen [17]3 years ago
8 0

Answer:

x=-\frac{41}{6}

Step-by-step explanation:

Pay attention to the two tick marks. This indicates that those sides are congruent to each other and so will the angles on the bottom and top. Therefore, we can set up the equation 137+2(-3x+1)=180 and solve for x:

137+2(-3x+1)=180

137+(-6x+2)=180

137-6x+2=180

139-6x=180

-6x=41

x=-\frac{41}{6}

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30 + 15 =45 dollars the first day, The second day 95 + 12 = 107 dollars the second day.
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you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.38, 1.18, 1.47, 1.35, 1.52
Talja [164]

For the given sample, mean = 1.306 and standard deviation = 0.1826.

As given ,

Given sample

x_{i}: 1.38, 1.18, 1.47, 1.35, 1.52, 1.23, 1.62, 1.17, 1.03, 1.11

Total samples N=10

Mean

 \bar{x} =\frac{\sum x_{i} }{N}

    = ( 1.38+1.18+ 1.47+ 1.35+ 1.52+ 1.23+ 1.62+ 1.17+ 1.03+1.11)/ 10

    = (13.06 ) /10

    = 1.306

(\sum x_{i} - \bar{x} ) ^{2} }  

= (1.38 -1.306)² + (1.18 -1.306)² +(1.47 -1.306)² +(1.35 -1.306)² +(1.52 -1.306)² +(1.23 -1.306)² +(1.62 -1.306)² +(1.17-1.306)² +(1.03 -1.306)² +(1.11 -1.306)²

=0.33344

Standard deviation =\sqrt{ \frac{(\sum x_{i} - \bar{x} ) ^{2} }{N} }

                              = \sqrt{\frac{0.33344}{10} }

                              = 0.1826

Therefore, for the given sample, mean = 1.306 and standard deviation = 0.1826.

Learn more about sample here

brainly.com/question/13287171

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8 0
2 years ago
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Serjik [45]
The number that is 150 more than the product of 5 and 4892 is 24700
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3 years ago
a toy store is having a sale a vis=deo game system has an original price of $99 it is on 40% off the original price
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Answer:

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Step-by-step explanation:

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3 years ago
Which of the following is the equation for the graph shown?
Marina86 [1]

The equation of an ellipse for the graph shown is \frac{x^2}{5^2} + \frac{y^2}{21^2} = 1

<h3>How to determine the equation?</h3>

Since the given coordinates of the vertices and foci have the form (-5, 0) and (5, 0) and (-2, 0) and (2, 0) respectively, this ultimately implies that the major axis of this ellipse is the x-axis.

Thus, the standard form of the equation of this ellipse is given by:

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Next, we would solve for b² by using this equation:

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Substituting the parameters into the standard equation of an ellipse, we have;

\frac{x^2}{5^2} + \frac{y^2}{21^2} = 1

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4 0
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