That's not a linear system, but you have an awesome school system for giving you this problem.

Multiply by 6xy to clear the fractions.

That's a second degree equation, also known as a conic. That one happens to be a hyperbola.


Let's clear the fractions from the second equation, multiplying out common denominator xy:


We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.
Substituting,





We have to rule out x=0 because it's in the denominator.


Answer: (44/19, 33/20)
Answer:x^2 + 9x + 20
Step-by-step explanation:
You could just multiply (x+4)(x+5) and get x^2 + 9x + 20, but judging from the picture, it looks like they want you to split it into 4 rectangles
x^2 +4x+ 5x + 20 =x^2 +9x + 20, just like (x+4)(x+5)
Answer:

Step-by-step explanation:
First we simplify:

Then we distribute:

Lastly, combine like terms:

Hope this helps!
Have a good evening! :)
Answer:
i think it would be 4x4=8+8=16
Answer:
We can use slope intercept form to get the points needed. Y= -7+1/3x The points are (0,-7) and (3,-6)
Step-by-step explanation:
Subtract 2x from the left side and place it over to the right side with the 42. Now we have -6y= 42-2x. From here we divide by -6 and we get y= -7+1/3x. We know that are slope is 1/3 which the one is the rise and the 3 is the run. We also know that our y intercept is -7. We plot the points at (0,-7) and (3,-6)