A chemistry examination has 2 sections.

Multiple regression is sometimes used in litigation. In the case of Cargill, Inc. v. Hardin, the prosecution charged that the ca

bogdanovich [222]

Answer:

($2.123 ; $2.149)

Step-by-step explanation:

The prediction interval is expressed as :

Predicted value ± standard Error

Predicted value = $2.136

Standard Error = $0.013

Prediction interval :

Lower boundary = $2.136 - $0.013 = $2.123

Upper boundary = $2.136 + $0.013 = $2.149

($2.123 ; $2.149)

B.) The prediction interval provides a range for which the predicted value or price should fall Given a certain degree of probability. If the true value falls within this interval, then, our prediction would be deemed to have occurred not by chance.

Since the actual price within the predicted price interval, then I agree with the judge's Decison that the price was not artificially depressed.

4 0

2 years ago

How do i solve 42 = -2d + 6

Mazyrski [523]

Substract 6 to both sides and you get 36 =-2d then you use the multiplicative inverse and d=-18.

8 0

3 years ago

Read 2 more answers

Is this a reflection

myrzilka [38]

Answer:

yes

Step-by-step explanation:

it is reflected across the y axis

4 0

2 years ago

What is the distance between 182 and 265 on a number line?

lawyer [7]

The correct answer is B. 83

5 0

3 years ago

Read 2 more answers

1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

so

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

so

the equation of the line is $y=-5x+3$

The inequality is $y>-5x+3$

3 0

3 years ago

Read 2 more answers