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emmainna [20.7K]
3 years ago
9

Which inequality represents the graph below?

Mathematics
2 answers:
diamong [38]3 years ago
7 0

the answer is x > -2

nasty-shy [4]3 years ago
3 0

x is greater then -2 and that is the 3 one


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Pls help or explain steps ​
Tems11 [23]

Solving for a variable means to rewrite the equation so that the desired variable is alone on one side. So, we have to "move" all the other variables/constants in order to make this happen. We are allowed to add/subtract the same quantity from both sides, or to multiply/divide both sides by any non-zero number.

Let's start with the first example: we are given

11. d=rt

the variable r is not alone on the right hand side because it is multiplied by t. We can reverse this by dividing both sides by t: the equation becomes

\dfrac{d}{t}=\dfrac{rt}{t}=r

So, we have written the equation as r=\frac{d}{t}, which means that r now sits alone on one side of the equation, and thus we have solved the equation for r!

Similarly, we do all the others:

12. f=v+at

Subtract at from both sides to get

f-at=v

13. Ax+By=C

Subtract By from both sides to get

Ax=C-By

Now divide both sides by A to get

x = \dfrac{C-By}{A}

14. A=\frac{1}{2}Pl

Multiply both sides by 2:

2A=Pl

Divide both sides by P:

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4 0
3 years ago
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The common ratio is 2<br><br><br> 40, 20, 10, 5,...
belka [17]

Answer:

2.5

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8 0
3 years ago
Solve each equation by graphing. Round to the nearest tenth.
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Answer:

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5 0
3 years ago
For 4 weeks, William volunteered as a helper for swimming classes. The first week, he volunteered for 8 hours. He volunteered fo
tino4ka555 [31]

Answer:

He volunteered 10 hrs 15 min on average.

Step-by-step explanation:

The first week: 8 hrs

The second week: 12 hrs

The third week: 12 hrs

The fourth week: 9 hrs

8 + 12 + 12 + 9 = 41 hrs total

41 hours/4 weeks = 10.25 hrs (10 hrs 15 min)

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#6<br> i<br> Find the value of each variable in the parallelogram.<br> 11<br> 14<br> C +5<br> d + 4
sergejj [24]

Answer:

c=6
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Step-by-step explanation:

d+4=14 and c+5=11

8 0
2 years ago
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