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3 years ago

Why does it help to rearrange

Mathematics

1 answer:

hichkok12 [17]3 years ago

8 0

Answer:

You don't really need to do it, but it helps you keep things more organized and easier to follow. Imagine if you're doing some multi-variable equation,

2a + 5b + 4d + 3c + b + a + 2d

that looks like a mess, it'll be easier to look at if you put all the similar variables next to each others like this:

a + 2a + b + 5b + 3c + 2d + 4d

(a + 2a) + (b + 5b) + 3c + (2d + 4d)

now you can add them up much easier.

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Pls help me with this

Bess [88]

Non proportional you can see by the way the graph is

8 0

3 years ago

4/5-2/15=<br><br><br><br> 4/7-2/8=<br><br><br><br> Find the difference

GenaCL600 [577]

1. 4/5 - 2/15 = 2/3

2. 4/7 - 2/8 9/28

5 0

3 years ago

Subject: [Mathematics]

Ivan

<h2>Answer: </h2><h2>3.19</h2><h2>______________________________________</h2><h3>Honey, all you need to do is multiply.</h3><h3>−2.75 by −1.16</h3><h2>______________________________________</h2>

Since the rational numbers are in parenthesis next to each other it means you have to multiply both of the numbers together.

Hope this helped at least a little bit!~

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7 0

3 years ago

Read 2 more answers

The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$