Answer:
the picture is blurry
Step-by-step explanation:
<h2>can. you give me another picture? plz</h2>

2) 5.625 mg will be left
Explanation:
1) Half-life = 17.5 days
initial amount of Arsenic-74 = 90 mg
To get the equation, we will use the equation of half-life:


2) we need to find the remaining amount of Arsenic-74 after 70 days
t = 70

So after 70 days, 5.625 mg will be left
90/3 parts of silver = 30 times multiplied by
tin = 12 × 30 = 360g
lead = 8 × 30 = 240g
12.5 / 23 = 0.5434 parts per metal
tin = 12 × 0.5434 = 6.5kg
lead = 8 × 0.5434 = 4.5kg
silver = 3 × 0.5434 = 1.5kg
Answer: itz d plz trust me
Answer:
A
Step-by-step explanation: