T(2.5) If t(x)= x^2 + 2x
where z = 2.5
t(x) = (2.5)^2 + 2(2.5)
6.25 + 5 =
11.25 = Ans
ANSWER
C.
EXPLANATION
The given function has range:
-3≤f(t)≤3
This implies that, the amplitude is
The function is symmetric with respect to the origin so this is a sine function.
This function is again reflected in the x-axis, hence
a=-3.
The period of this function is
This implies that, b=3,
hence the equation of the function is
0.00373134328
I think you can round that but I think that's the answer.
<u>(x-5)²+(y-5)²=36</u>
Answer:
Solution given:
radius [r]=6 units
centre[h,k]=(5,4)
we have
the equation of a circle is;
(x-h)²+(y-k)²=r²
(x-5)²+(y-5)²=6²
<u>(</u><u>x-5</u><u>)</u><u>²</u><u>+</u><u>(</u><u>y-5</u><u>)</u><u>²</u><u>=</u><u>3</u><u>6</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>circle</u><u>.</u>
Wait is this the problem?
