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Rzqust [24]
3 years ago
13

Please help out with this question..

Mathematics
1 answer:
Sophie [7]3 years ago
8 0

Answer:

Step-by-step explanation:

C = 16 * 3 = 48

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Bag A: Two thirds of the candies are yellow. What portion of the candies is green
dalvyx [7]

Answer: \frac{1}{3} proportion of candies are green.  

Solution:  

In bag A, \frac{2}{3} candies are yellow.  

\frac{2}{3} this proportion shows ratio of favorable over total candies.  

Here numerator number is 2.  

So, Total number of yellow candies should be 2x

Total number of candies in Bag A would be 3x

Number of green candies in bag A = 3x-2x = x

Now we find the portion of green candies in bag A

\therefore,  \frac{x}{3x}

\frac{1}{3} portion of candies are green in bag A

7 0
3 years ago
If Ray QS bisects angle PQR , m of angle PQS=7x-6 and m of angle SQR =4x+15,find m of angle PQT
lys-0071 [83]

"Bisect" is a mathematical term which means to divide into two equal parts. We can bisect angles, lines, and more. The line that divides is called the "bisector". 
sample problem:

<span> If Ray QS bisects angle PQR , m of angle PQS=7x-6 and m of angle SQR =4x+15,find m of angle PQT.

Since it is mentioned that ray QS bisects the angle PQR, it is understood that the m of angle of PQT is </span><span><span>4x+15. It is because as metioned earlier, to bisect angles or lines, it means dividing into 2 equal parts, thus, bisect equal measurements of angles.

</span></span>






8 0
3 years ago
Bárbara come la tercera parte de una caja de bombones. Su papá luego compra 7 bombones más y los pone en la caja. ¿Cómo se repre
Maksim231197 [3]

Answer:

Bárbara come la tercera parte de una caja de bombones. Su papá luego compra 7 bombones más y los pone en la caja. ¿Cómo se representa la cantidad de bombones que hay ahora en la caja?

Step-by-step explanation:

3 0
3 years ago
Two numbers given in certain radix x are (55)x and (64)x . If we add this two numbers, the result is (130)x. What is the radix x
wlad13 [49]

the answer is x = 9.

4 0
3 years ago
If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.
Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

<em></em>

Step-by-step explanation:

Given

f(x)=x^3-12x^2+35x-24

f(8) = 0

Required

Find all zeros of the f(x)

If f(8) = 0 then:

x = 8

And x - 8 is a factor

Divide f(x) by x - 8

\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}

Expand the numerator

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}

Rewrite as:

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}

Factorize

\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}

Expand

\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}

Factorize

\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}

\frac{f(x)}{x - 8} = (x - 1)(x - 3)

Multiply both sides by x - 8

f(x) = (x - 1)(x - 3)(x - 8)

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

7 0
3 years ago
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