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Llana [10]
3 years ago
6

I will give brainliest to whoever answers this question:) help a dummy out

Mathematics
2 answers:
Kay [80]3 years ago
7 0

Answer:

Step-by-step explanation:

The equation is a parabola, that opens up downwards,  and the point from which Sarah throws the ball is 5 feet off the ground.  so set the height to zero ( when the ball reaches the ground )  and solve for t

0 = -16t^{2} + 18t + 5

use quadratic equation :)

-b +- sqrt(b^{2} - 4ac) / 2a

-18 +- sqrt[ 18^{2} - 4 (-16)(5) ] / 2(-16)

-18 +- sqrt[324 +320 ] / -32

-18 +- sqrt[644] / -32

-18 +- 25.377155 / -32

do the positive choice :

-18 + 25.377155 / -32

7.377155  / -32

-0.2305  ( so this answer would be where the ball would hit the ground if the arc extended down to the ground behind where Sarah throws the ball from. so this answer doesn't count in our domain. Because it's before Sarah throws the ball)

do the negative choice:

-18 - 25.377155 / -32

1.355536  ( this answer looks good, about 1.35 seconds for the ball to fly , this was more of a toss than a throw. )

t = 1.4 seconds ( rounded to nearest 10th )

aliya0001 [1]3 years ago
5 0

Answer:

Step-by-step explanation:

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Lady bird [3.3K]

Answer: Choice B) -5.2 degrees

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Work Shown:

Add up the given temperatures

-42 + (-17) + 14 + (-4) + 23 = -26

Then divide by 5 since there are 5 values we're given

-26/5 = -5.2

6 0
3 years ago
Perímetro de un cubo de 9 cm​
svp [43]

Answer:

Perímetro de

Step-by-step explanation:

What does this mean?

5 0
3 years ago
Write in standard notation (1/sqrt2-1/sqrt2 i)^6
vesna_86 [32]
Hello,

z=(1/√2-1/√2 i)^6=1/8*(1-i)^6=1/8*(√2∡-45°)^6=1/8*8∡-270°=1∡90°=i
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7 0
3 years ago
Prove that <br><img src="https://tex.z-dn.net/?f=4cot45%20%5E%7B2%7D%20%20-%203tan%20%5E%7B2%7D%2060%20%2B%202sec%20%5E%7B2%7D60
sesenic [268]

Answer:

4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  = 3 \\

LHS = 4 \cot {}^{2} (45)  - 3 \tan {}^{2} (60)  + 2 \sec {}^{2} (60)  \\

let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.

here ,

\cot(45)  = 1 \\  \\  \tan(60)  =  \sqrt{3}  \\  \\  \sec(60)  = 2

now ,

we just have to plug in the values considering certain other things given in the question and we're done!

so let's start ~

4(1) {}^{2}  - 3( \sqrt{3} ) {}^{2}  + 2(2) {}^{2}  \\ \\ \dashrightarrow \: 4(1) - 3(3) + 2(4) \\ \\ \dashrightarrow \: 4 - 9 + 8 \\\\ \dashrightarrow \: 12 - 9 \\ \\\dashrightarrow \: 3 = RHS

hence , proved ~

hope helpful :D

7 0
3 years ago
Passes through (2,3) and has slope of -1
anzhelika [568]
Y=2x-1 i think that would be your answer.
4 0
4 years ago
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