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RSB [31]
3 years ago
9

A flower bed has the shape of a rectangle 27 feet long and 9 feet wide. What is its area in square yards

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0
Area of a rectangle = bh or lw

A = 27(9)

A = 243 feet

There are 3 feet in a yard

243/3 = 81

The flower bed is 81 square yards
deff fn [24]3 years ago
3 0
The answer to this question is 243 square yards

27 x 9 = 243
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A rectangle is 6 feet long by 4 feet wide.
Slav-nsk [51]

Answer:

6 - 2=4

4 x 4= 16

Step-by-step explanation:

4 0
3 years ago
A polynomial function can be written as (x - 2)(x - 3)(x + 5) What are the x-intercepts of the graph of this function? (4 points
Dvinal [7]
Easy
the x intercepts are the roots
for roots, r1,r2,r3, the factors are
(x-r1)(x-r2)(x-r3)
given
(x-2)(x-3)(x-(-5))
the roots are
x=2,x=3,x=-5

so
(2,0) and (3,0) and (-5,0)

first opiton
3 0
3 years ago
Read 2 more answers
What is the answer to <br> 2/5 =2/10+k
exis [7]
2/5 = 2/10 + k
multiply both sides (each term) by 10, we get
10×2/5 = 10× 2/10 + k ×10
4 = 2 + 10k
OR 10k = 4 - 2
10 k = 2
k = 2 / 10
Or k = 1/5



8 0
3 years ago
Read 2 more answers
Help solve for x please (ignore my incorrect math)
IgorLugansk [536]

140° + ∠5 = 180°    <em>same side interior angles    </em>⇒  ∠5 = 40°

∠2 ≅ ∠5    <em>vertical angles   ⇒ </em>∠2 = 40°

∠8 = 53°   <em>alternate interior angles</em>

∠3 ≅ ∠8   <em>vertical angles  ⇒ </em>∠3 = 53°

x + ∠2 + ∠3 = 180°  <em>triangle sum theorem</em>

x + 40° + 53° = 180°

x + 93° = 180°

x = 87°

Answer: 87°

Note: I just realized that there is an easier way to solve this:

∠9 + 53° + x = 180°   <em>triangle sum theorem</em>

140° + ∠9 = 180°  <em>supplementary angles </em>⇒  ∠9 = 40°

40° + 53° + x = 180°  

x + 93° = 180°

x = 87°

Use whichever solutions makes sense to you.


     

7 0
3 years ago
PLEASE HELP!!
jeka94

Based on my experiences so far, the approach to geometry that I prefer is: Euclidean Geometry. This is because the problems are easy to visualize since they are restricted to two-dimensional planes.

<h3>Which approach is easier to extend beyond two dimensions?</h3>

The approach that is easier to extend beyond two dimensions is Euclidean Geometry. Again, this is because of how it deals with shapes and visualization of the same.

Take for instance a triangle; it is easy to go from a two-dimensional equilateral triangle  to a square pyramid.

<h3> What are some situations in which one approach to geometry would prove more beneficial than the other?</h3>

Analytical geometry is a superior technique for discovering objects (points, curves, and planes) based on their qualities in some situations than Euclidean geometry is in others (for example, when employing topography or building charts).

Learn more about Euclidean Geometry at;
brainly.com/question/2251564
#SPJ1

3 0
2 years ago
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