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konstantin123 [22]
3 years ago
9

Choose the equation below that represents the line passing through the point (1, -4) with a slope of 1/2

Mathematics
1 answer:
tatiyna3 years ago
6 0

For this case we have that by definition, the line equation of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the statement we have:

m = \frac {1} {2}

Thus, the equation is of the form:

y = \frac {1} {2} x + b

We substitute the given point and find "b":

-4 = \frac {1} {2} (1) + b\\-4 = \frac {1} {2} + b\\-4- \frac {1} {2} = b\\b = - \frac {9} {2}

Finally, the equation is of the form:

y = \frac {1} {2} x- \frac {9} {2}

Answer:

y = \frac {1} {2} x- \frac {9} {2}

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Zolol [24]
16 because 10+8=18 and 18-2=16
8 0
3 years ago
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Help please This is 8th grade made. I put 13 but Idk if it's correct
Rom4ik [11]
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5 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
Lin sold 4 more shirts than Greg. Fran sold 3 times as many shirts as Lin. In total the three sold 51 shirts. Which represents t
Alex17521 [72]
 <span>Your Answer: D 

Why.... 

You can make equations out of the information 
Let L be Lin, G be Greg, and F be Fran 

L = 4 + G ---"Lin sold 4 more shirts than Greg" 
F = 3L ---"Fran sold 3 times as many shirts as Lin" 
F + G + L = 51 ---"In total the three sold 51 shirts" 

Use F + G + L = 51 
Substitute the equations in for F and L (because you need to know the G) like this.... 

(3L) + G + (4+G) = 51 

You still have a variable besides G in there... you can use the L= 4+G and substitute again so that there are only G's 

( 3(4+G) ) + G + (4+G) = 51 ---- SIMPLIFY :D 
( 12 + 3G ) + G + 4 + G = 51 
12 + 3G + G + 4 + G = 51 ---Combine like terms 
16 + 5G = 51 </span>
6 0
3 years ago
Write a system of equations that could be used to solve the situation described below.
attashe74 [19]

If there are 12 coins under the couch and every coin is either a nickel or a penny and together they are forming 32 cents then the equations which represent the problem will be x+y=12, 0.01x+0.05y=0.32. The correct option is B which is x+y=12, 0.01x+0.05y=0.32.

Given There are 12 coins and total money is 32 cents.

Let the number of pennies be x and the number of  nickels be y.

According to question there are 12 coins so the first equation becomes:

x+y=12.

Then we have been told that together they amount to 32 cents.

We know that 1 penny is 1 cent coin and 1 nickel is 5 cent coin so the equation becomes :

1*x+5*x=32

x+5y=32

converting into dollar

0.01x+0.05y=0.32.

Hence the right equations showing the problem of nickel and pennies are x+y=12, 0.01x+0.05y=0.32.

Learn more about equations here brainly.com/question/2972832

#SPJ10

3 0
1 year ago
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