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3 years ago

Solve this system by substitution, y = 3 y=-3x + 6 *Remember to write your answer as a coordinate point (x, y). I

1 answer:

7 0

Take y=3 and plug it into y=-3x+6. This gives you 3=-3x+6. Solve for x, you get x=1. Now plug 1 into y=-3x+6 and you get 3. Answer is (1,3)

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PLEASE HELP ANSWER THIS ASAP!!! :)

PilotLPTM [1.2K]

Answer:

C, 42 degrees

Step-by-step explanation:

Considering angle BAD is 60 degrees, that makes angle BCD also 60 degrees. Since parallelograms have 360 degrees in total, we're still missing 240 degrees. Since angles BAD and BCD are congruent (equal), that means that angles ABC and ADC also have to be congruent. To find their angles, we do 240 divided by 2, which equals 120. Now that we know all of the angles, lets focus on angle ADC. Since angle 1 has been given to us, all we need to do is subtract 78 from 120 which turns out to be 42 degrees, which is the answer.

5 0

3 years ago

Divide. Express your answer as a mixed number in simplest form. Enter your answer in the box.

balandron [24]

Answer:

63/4

Step-by-step explanation:

First convert mixed fraction into a fraction=21/4 (5x4+1)

Fractions can not be solved with division sign so turn it in a multiplication sign through reciprocal.

21/4 x 3/1

63/4

8 0

3 years ago

At a concession stand, one hot dog and one hamburger cost $3.75 ; one hot dog and cost $12.25 . Find the cost of one hot dog

raketka [301]

The function shows that the cost of hotdogs is 1.75 and the cost of hamburger is 1.5.

<h3>How to calculate the information?</h3>

Let hotdogs = h

Let hamburger = x

The expression will be:

h + x = 3.25

h + 7x = 12.25

Subtract the functions

6x = 9

x = 1.5

Therefore, hot dogs will be:

= 3.25 - 1.5

= 1.75

Learn more about expressions on:

brainly.com/question/723406

#SPJ1

At a concession stand, one hot dog and one hamburger cost $3.25; one hot dog and seven hamburger cost $12.25. Find the cost of one hotdog and the cost of one hamburger.

8 0

2 years ago

The sum of the first n terms of a geometric series is 364? The sum of their reciprocals 364/243. If the first term is 1, find n

Afina-wow [57]

If the geometric series has first term $a$ and common ratio $r$ , then its $N$ -th partial sum is

$\displaystyle S_N = \sum_{n=1}^N ar^{n-1} = a + ar + ar^2 + \cdots + ar^{N-1}$

Multiply both sides by $r$ , then subtract $rS_N$ from $S_N$ to eliminate all the middle terms and solve for $S_N$ :

$rS_N = ar + ar^2 + ar^3 + \cdots + ar^N$

$\implies (1 - r) S_N = a - ar^N$

$\implies S_N = \dfrac{a(1-r^N)}{1-r}$

The $N$ -th partial sum for the series of reciprocal terms (denoted by $S'_N$ ) can be computed similarly:

$\displaystyle S'_N = \sum_{n=1}^N \frac1{ar^{N-1}} = \frac1a + \frac1{ar} + \frac1{ar^2} + \cdots + \frac1{ar^{N-1}}$

$\dfrac{S'_N}r = \dfrac1{ar} + \dfrac1{ar^2} + \dfrac1{ar^3} + \cdots + \dfrac1{ar^N}$

$\implies \left(1 - \dfrac1r\right) S'_N = \dfrac1a - \dfrac1{ar^N}$

$\implies S'_N = \dfrac{1 - \frac1{r^N}}{a\left(1 - \frac1r\right)} = \dfrac{r^N - 1}{a(r^N - r^{N-1})} = \dfrac{1 - r^N}{a r^{N-1} (1 - r)}$

We're given that $a=1$ , and the sum of the first $n$ terms of the series is

$S_n = \dfrac{1-r^n}{1-r} = 364$

and the sum of their reciprocals is

$S'_n = \dfrac{1 - r^n}{r^{n-1}(1 - r)} = \dfrac{364}{243}$

By substitution,

$\dfrac{1 - r^n}{r^{n-1}(1-r)} = \dfrac{364}{r^{n-1}} = \dfrac{364}{243} \implies r^{n-1} = 243$

Manipulating the $S_n$ equation gives

$\dfrac{1 - r^n}{1-r} = 364 \implies r (364 - r^{n-1}) = 363$

so that substituting again yields

$r (364 - 243) = 363 \implies 121r = 363 \implies \boxed{r=3}$

and it follows that

$r^{n-1} = 243 \implies 3^{n-1} = 3^5 \implies n-1 = 5 \implies \boxed{n=6}$

5 0

2 years ago

Can i reduce 7/20 into a lower term?

larisa86 [58]

No nothing can go into 7 evenly except 7 but that doesn’t go into 20 evenly so your answer is no

6 0

3 years ago

Solve this system by substitution, y = 3 y=-3x + 6 *Remember to write your answer as a coordinate point (x, y). I​

Solve this system by substitution, y = 3 y=-3x + 6 *Remember to write your answer as a coordinate point (x, y). I