3 years ago

Whch expression could be used to change 8 kilometers per hour to meters per minute

Mathematics

1 answer:

vazorg [7]3 years ago

5 0

Answer:

133.33 meters per minute.

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What is the range of the given function? {(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}

Natali5045456 [20]

Answer: R = {0, -3, -9, 5, 7}

Explanation: The range is the set of all y-coordinates for our ordered pairs.

So the range for this relation is {0, -3, -9, 5, 7}.

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3 years ago

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If a square has a perimeter of 36 in. what is the Circumstances of the circle?given the exact answer in terms of pi.

vfiekz [6]

Answer:

a)B)9π

b)G)16π in²

Step-by-step explanation:

according to the question

$64 \times \frac{\pi}{4}$

$16\pi \: {in}^{2}$

as we know

C/d=π

C=dπ

Therefore

C=9π

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2 years ago

If the diameter of the small pizza is 8 inches, what’s the pizza’s area in square inches?

abruzzese [7]

Answer:

Step-by-step explanation: $\pi$ x8x8=201.06192983square inches

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3 years ago

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Which equation is related to x+23=9?.

cestrela7 [59]

If x +23 = 9, then, x = 9-23.

So x = -14

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A population has a known standard deviation of 1.27 and a sample space contains 85 values find the margin of error needed to cre

r-ruslan [8.4K]

Answer:

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this question:

$\sigma = 1.27, n = 85$

$M = z*\frac{\sigma}{\sqrt{n}}$

$M = 2.575*\frac{1.27}{\sqrt{85}}$

$M = 0.3547$

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

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3 years ago