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2 years ago

Hal earns $5 a week doing chores for his parents. He also earns $10 a week for each dog, d, he walks

Mathematics

1 answer:

ZanzabumX [31]2 years ago

5 0

Answer:

Step-by-step ex

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PLS HURRY IM BEING TIMED

mrs_skeptik [129]

Answer:

I believe it is 0.8(0.0675f) + 0.55(0.0675m)

Step-by-step explanation:

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2 years ago

Which are the solutions of x2 = –13x – 4? 0, 13 0, –13 StartFraction 13 minus StartRoot 153 EndRoot Over 2 EndFraction comma Sta

klasskru [66]

Solution of the given expression $x^2 = -13x-4$ is $x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Step-by-step explanation:

We need to find solutions of $x^2 = -13x-4$

We need to solve the quadratic equation and find values of x.

Solving:

$x^2 = -13x-4$

Rearranging the terms:

$x^2+13x+4=0$

Solving the quadratic equation using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a = 1, b= 13 and c=4

putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(13)\pm\sqrt{(13)^2-4(1)(4)}}{2(1)}\\x=\frac{-13\pm\sqrt{169-16}}{2}\\x=\frac{-13\pm\sqrt{153}}{2}\\x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

So, Solution of the given expression $x^2 = -13x-4$ is $x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}$

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

#learnwithBrainly

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2 years ago

Read 2 more answers

PLS HELP ASAP

ivanzaharov [21]

Answer:

hope it helps

.........

7 0

2 years ago

The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt, where P is the in

Maslowich

Answer:

8333.33

Step-by-step explanation:

Given that the rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt, where P is the initial rate. Use the improper integral

∫^[infinity]_0 Pe^-kt dt

with P = 50 to find the total amount of the waste that will enter the atmosphere for each value of k.

k=0.06

Hence the total amount of waste that can enter the atmosphere when k =0.06 is given by

$\int\limits^{\infty} _0 {50e^{-0.06t} } \, dt\\=-\frac{50}{0.006} e^{-0.06t}$

Substitute limits

=8333.33

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3 years ago

Each big square below represents one whole,

lukranit [14]

The first square is 100% and the second square is 55% filled in

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2 years ago