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2 years ago

The length of a rectangle is 4 meters less then 3 times the width. The perimeter is 16 meters. Find the width

Mathematics

1 answer:

tigry1 [53]2 years ago

7 0

Solution :

Given :

Perimeter, P = 16 m

The length is 4 times less then three times the width.

Let the length be l and width be w.

Therefore, according to the equation :

Length, l = 3w - 4 ................(i)

Perimeter, P = 2(l+w)

16 = 2(l+w) ............(ii)

16 = 2l + 2w

8 = l + w ..............(iii)

Therefore solving equation (i) and (iii)

l = 3w - 4

8 = l + w

We get, w = 3 and l = 5

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2 years ago

{96/[36/3-(18 x 2 - 30)]} / (31-16+1)

ehidna [41]

Answer:

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2 years ago

Directions: Find the complemen

andre [41]

Given:

The angles are:

Example $54^\circ$

1. $63^\circ$

2. $87^\circ$

3. $45^\circ$

4. $72^\circ$

5. $5^\circ$

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of $54^\circ$ , then

$x+54^\circ=90^\circ$

$x=90^\circ -54^\circ$

$x=36^\circ$

Similarly,

1. The complimentary angle of $63^\circ$ is:

$90^\circ -63^\circ=27^\circ$

2. The complimentary angle of $87^\circ$ is:

$90^\circ -87^\circ=3^\circ$

3. The complimentary angle of $45^\circ$ is:

$90^\circ -45^\circ=45^\circ$

4. The complimentary angle of $72^\circ$ is:

$90^\circ -72^\circ=18^\circ$

5. The complimentary angle of $5^\circ$ is:

$90^\circ -5^\circ=85^\circ$

Therefore, the complimentary angles of $54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ$ are $36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ$ respectively.

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2 years ago